Class 12th
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New answer posted
a year agoContributor-Level 10
Among its different uses noradrenaline is used as an anti-depressant.
New answer posted
a year agoContributor-Level 10
ρ = M/V
∴ 6.17 = (2 x MX? ) / (N? x (300 x 10? ¹? )³)
Solving MX? = 50 g
∴ No. of molecules in 200 g
= (200/50) x N? = 4 N?
New answer posted
a year agoContributor-Level 10
Initial charge Q = CV = 14 * 10? ¹² * 12 = 168 * 10? ¹² C
Initial energy U_in = ½ CV² = ½ (14 * 10? ¹²) * 12² = 1008 pJ
When the battery is disconnected and a dielectric (k=7) is inserted, the new capacitance is C' = kC.
The charge Q remains constant.
Final energy U_f = Q²/2C' = Q²/ (2kC) = (CV)²/ (2kC) = CV²/ (2k)
U_f = (14 * 10? ¹² * 12²) / (2 * 7) = 144 pJ
Mechanical energy available for oscillation
New answer posted
a year agoContributor-Level 10
For A
0.693/300 = (2.303/t) log (A? /A? )
For B
0.693/180 = (2.303/t) log (B? /B? )
Given A? = B? & A? = 4B?
Substituting & solving we get t = 900 s
New answer posted
a year agoContributor-Level 10
I = I? sin (ωt) + I? cos (ωt)
This can be written as I = I? sin (ωt + φ), where I? = √ (I? ² + I? ²)
A hot wire ammeter reads the rms value of the current.
I_rms = I? /√2 = √ (I? ² + I? ²)/√2
New answer posted
a year agoContributor-Level 10
At CMC, the particles cluster together through lyophobic end to form associated colloid called micelle. Further all lyophilic ends (polar head) get projected towards water.
New answer posted
a year agoContributor-Level 10
E_ground (H-atom) = -13.6 eV
E_carbon = E_ground (H-atom) * Z²/n²
For carbon, Z=6.
-13.6 eV = -13.6 eV * (6²/n²)
1 = 36/n²
n² = 36
n = 6
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