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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

∫ [π/6 to π/3] (d/dx (tan? x) * sin³3x + tan? x * d/dx (sin³3x) dx
= 1/2 ∫ [π/6 to π/3] d/dx (tan? x * sin?3x) dx
= 1/2 [tan? x · sin?3x] from π/6 to π/3
= 1/2 [ (√3)? · 0 - 1/ (√3)? )]
= -1/18

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

(I) Lucas reagent → Only ZnCl? /Conc. HCl
(II) Dumas method → CuO/Δ
(III) Kjeldahl's method → Conc. H? SO? /Δ
(IV) Heinsberg reagent → C? H? SO? Cl/ aq. NaOH

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Here,
| 1 |
| 2 4 -1 | = 0 ⇒ λ = 9/2
| 3 2 λ |

Also,
| 1 2 |
| 2 4 6 | = 0 ⇒ μ = 5
| 3 2 μ |

∴ Option B is correct.

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

For d? configuration if Δ? < P the electronic configuration is t? g eg


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2 months ago

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A
alok kumar singh

Contributor-Level 10

Zn, Cd&Hg are purified by fractional distillation process.

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New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

In the ccp lattice of oxide ions effective number of O? ² ions = 8 *? + 6 * ½ = 4
In the ccp lattice,
No. of octahedral voids = 4
No. of tetrahedral voids = 8
Given M? atoms occupies 50% of octahedral voids and M? atoms occupies 12.5 of tetrahedral voids
No. of M? metal atoms = 4 *? /? = 2
No. of M? metal atoms = 8 * ¹²·? /? = 1
∴ Formula of the compound = (M? )? (M? )O?
∴ Oxidation states of metals M? & M? respectively are +2 and +4 .

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2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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E
Esha Garg

Beginner-Level 5

The nature of bonding in Ni (CO)? includes synergic bonding. The synergic bonding in metal carbonyls like nickel tetracarbonyl is due to two-way interaction of metal and carbonyl ligand electron density donation.

The synergic bonding is best explained thorugh Molecular Orbital Theory (MOT), which explains the donation of electron density from the filled d-orbitals of nickel (Ni) into the antibonding? * orbitals of the carbon monoxide (CO) ligand.

The synergic bonding can be described as a combination of? -bond formation due to donation of lone pair to metal center, and? back-bond formation due to donation of lone pair to CO ligand. 

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2 months ago

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S
Satyendra Dhyani

Beginner-Level 5

The metal-carbon bonds (M-C) in metal carbonyls are due to the synergic interaction between the metal and carbonyl group. There are two types of bonding between metal and carbonyl group. 

? -bond in Metal Carbonyls: The Carbonyl (CO) ligand donates a lone pair of electrons to the metal center to fill its empty d-filled orbital. This electron density donation is called? -donation.

? -back bond in Metal Carbonyls: This is the case of back bonding. The already filled d-orbitals return the electron density into the empty? * (antibonding) orbital of CO. This electron density donation by the metal is called? -back donation.

Both these comb

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