Class 12th
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New question posted
7 months agoNew answer posted
7 months agoContributor-Level 10
Charge (q) = (it/96500) F = (1x15x60)/96500 = 900/96500 = 9/965 F = 0.0093F
No. of moles of Au? = 0.025 & No. of moles of Ag? = 0.025
Species with higher value of SRP will get deposited first at cathode.
(i) Au? (aqs) + e? → Au (s)
0.025 0.0093 mole
So only Au will get deposited
New answer posted
7 months agoContributor-Level 10
In Calcination and roasting CO? and SO? are released which are responsible for Global warning and acid rain.
New answer posted
7 months agoContributor-Level 10
[Co (H? O)? F? ]Co³? = 3d?4s? ⇒ t? g²? ¹? ¹ e? ¹? ¹
CFSE = [−0.4nt? g + 0.6neg]? o + n (P)
= [−0.4 * 4 + 0.6 * 2]? o + 0 = −0.4? o
New answer posted
7 months agoContributor-Level 10
We know I = 4I? cos² (φ/2) but φ = 2πx/λ
I = 4I? cos² (πx/λ)
(i) when x = λ, I = k
i.e. k = 4I? cos²π
k = 4I?
(ii) when x = λ/6
I' = kcos² (π (λ/6)/λ) = kcos² (π/6) = k (√3/2)²
I' = 3k/4
Correction from image: The provided image has an error in the calculation. I' = k ( (√3/2)² ) = 3k/4. The image shows 9k/12 which simplifies to 3k/4. I will use the value from the OCR which seems to be a typo.
I' = kcos² (π/6) = k (3/4)
I' = 9k/12
New answer posted
7 months agoContributor-Level 10
λ = 6 * 10? M
d = 6 x 10? M
I = I? [ (sin (β)²/β²] ; β = (πdsinθ)/λ
θ = π/2 ; β = πd/λ
= (π (6 * 10? )/ (6 x 10? ) = 100π
So at ∞ also minima will form total number of minima = 2 * 100 = 200
New answer posted
7 months agoContributor-Level 10
i? = 40/100 = 2/5
i? = 40/200 = 1/5
V? – V? = 40i? = 40 * 2/5
V? – V? = 16
V? – Vd = 90i? = 90/5 = 18
V? – Vd = 18 – 16 = 2 volt
New answer posted
7 months agoContributor-Level 10
P = 1/f = (N/100)D
2x + 40 = 100
x = 30 cm
100 – x = 70 cm
1/v - 1/u = 1/f
1/70 - 1/ (-30) = 1/f
1/f = 1/70 + 1/30 = (3+7)/210 = 1/21
f = 21 cm = 0.21M
Power = 1/f = 1/0.21; D = (100)/21
N/100 D = 100/21
N = 10000/21 = 476.19
N = 476
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