Class 12th
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New answer posted
2 months agoContributor-Level 9
first order reaction
K = (2.303/t) log (a? / (a? - x)
K = (2.303/90) log (a? / 0.25a? ) = 0.0154
t = 60% = (2.303/K) log (a? / a? ) . (2)
= (2.303 / 0.0154) x (1 - 0.602) = 59.51 mins ≈ 60
New answer posted
2 months agoContributor-Level 9
P? = X? (P? – P? ) + P?
ATQ
550 = 1/4 (P? – P? ) + P?
2200 = P? – P? + 4P?
560 = 1/5 (P? – P? ) + P?
2200 = P? – P? + 5P?
P? + 3P? = 2200
P? + 4P? = 2800
P? = 600
P? = 400 mmHg
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2 months agoContributor-Level 10
Charge (q) = (it/96500) F = (1x15x60)/96500 = 900/96500 = 9/965 F = 0.0093F
No. of moles of Au? = 0.025 & No. of moles of Ag? = 0.025
Species with higher value of SRP will get deposited first at cathode.
(i) Au? (aqs) + e? → Au (s)
0.025 0.0093 mole
So only Au will get deposited
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