Class 12th
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New answer posted
4 months agoContributor-Level 10
P = (μ – 1) (1/R – 1/ (-R)
P = 2 (μ – 1)/R
1.5P = (μ – 1)/R') * 1.5 = 1/2R'
R' = R/3
New question posted
4 months agoNew answer posted
4 months agoNew answer posted
4 months agoContributor-Level 10
i = V/r {1 - e? /? }
i? = V/r
U = ½Li²
½ L (V²/r²) {1 - e? /? } = (1/n) x (LV²/2r²)
1 - e? /? = 1/√n ; e? /? = 1 - 1/√n = (√n - 1)/√n
e? /? = √n/ (√n - 1) ; rt/L = ln (√n/ (√n - 1)
T = L/r ln (√n/ (√n - 1)
New question posted
4 months agoNew answer posted
4 months agoContributor-Level 10
In Ohm's law experiment, ammeter is used in series because in series same current will flow through it. But voltmeter is used in parallel to resistor to measure the potential difference across it.
New answer posted
4 months agoContributor-Level 10
Total mass of reactant should be greater than that of product.
This condition is only fulfilled in case- 3
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