Class 12th

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New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

Two linkage isomers

 

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Total mass of reactant should be greater than that of product.
This condition is only fulfilled in case- 3

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

2 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

i? = 8/8 = 1 A    

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

E = E? (1 − ax²)

F = qE?
acceleration = F/m = (qE? /m) (1 - ax²) = v (dv/dx)
(qE? /m) ∫? (1 - ax²)dx = ∫? vdv; (qE? /M) (x - ax³/3) = 0
x (1 - ax²/3) = 0; x = 0 & x = √ (3/a)

New answer posted

2 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

SN2 is a bimolecular reaction. This is because as per the rate law,
Rate = k [substrate] [nucleophile]

Here, the rate determining step is dependent on both substrate and nucleophile, unlike SN1 who only involves substrate. Therefore, SN2 is proved to be bimolecular.

New question posted

2 months ago

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New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

A - B has the lowest potential energy and it means it has stronger bond.

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

Binding energy = (50M? + 70M? – Msn)C²
= (50.3915 + 70.6069 – 119.902199)U²
= (1.0962U)C²
= 931 * 1.0962MeV

Binding energy per neucleon
= (931 x 1.0962)/120 MeV
= 8.5MeV

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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