Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
12k

Questions

0

Discussions

63

Active Users

0

Followers

New answer posted

4 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

4 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Voltage across secondary source
P = V? i? = V? i?
V? = P/i? = 60/0.11 ≈ 545 V
Since voltage across secondary source is more than primary source (220V)
⇒ Step- up transformer.

New answer posted

4 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

According to Question, we can write
E = λ/ (2πε? r) ⇒ σ = ε? E = λ/ (2πr)
⇒ σ = 8*10? / (2*3.14*3) = 0.424 nCm? ²

New answer posted

4 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

4 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

4 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Using lens maker formula, we can write
1/f = (µ/µ? - 1) (1/R? - 1/R? )
µ = µ? ⇒ 1/f = 0 ⇒ f → Infinite

 

New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Using de-Broglie equation:
λ = h/p = h/√ (2mK) = h/√ (2meV)
λ ∝ 1/√m
λ? /λ? = √ (m? /m? ) = √ (1.00727/0.00055) = √1831 ≈ 43:1

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

A = Activity = λN = (ln (2)/t? /? ) N
N = (1.5*10? ³ / 198) * 6*10²³
A = (0.693 / (2.7*24*3600) * (1.5*10? ³ / 198) * 6*10²³ disintegration/s
A ≈ 1.32 * 10¹³ Bq = (1.32*10¹³ / 3.7*10¹? ) Ci ≈ 357 Ci

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

d = √ (2hT R) + √ (2hR R) = 2√ (2hR) (assuming towers are identical)
h = d²/ (8R) = (45*10³)²/ (8*6400*10³) ≈ 39.55 m

 

New answer posted

4 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

As we know that magnetic force acting on a charge particle will be
F = q (v * B)
W = F.dl
Since force and displacement will be always perpendicular so work done is always zero.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 681k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.