Class 12th

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New answer posted

7 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

  I = 1 2.5 = 0.4 A

I = I 2 = 0.2 A

 

New answer posted

7 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

ε = - d φ d t = - A d B d t

= ( 16 * 4 - 4 * 2 ) ( 1000 - 500 ) 5 * 10 - 4 * 10 - 4

= 56 * 500 5 * 10 - 8 = 56 * 10 - 6 V

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Capacitance of element

Capacitance of element, C ' = K ( 1 + α x ) ε 0 A d x

1 C ' = 0 d ? d x K ε 0 A ( 1 + α x )

1 C = 1 K ε 0 A α l n ? ( 1 + α d )

Given: α d ? 1

1 C = 1 K ε 0 A α α d - α 2 d 2 2 ; 1 C = d K ε 0 A 1 - α d 2

C = K ε 0 A d 1 + α d 2

 

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

A = A 0 e - λ t

500 = 700 e - λ t λ t = l n ? 7 5 l n ? 2 t 1 / 2 * 30 = l n ? 7 5 ? t 1 / 2 = l n ? 2 * 30 l n ? 7 5

t 1 / 2 = 61.8 m i n 62 m i n .

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

For 2 nd    minima

d s i n ? θ = 2 λ

s i n ? θ = 3 2   (given)

λ d = 3 4

So for 1 st    minima is

d s i n ? θ = λ

s i n ? θ = λ d = 3 4   (from equation (i)

θ = 25.65 ?   (from sin table)

  θ 25 ? .

New answer posted

7 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

x = retentivity

y = coercivity

z = saturation magnetization

 

New answer posted

7 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

  I = I 0 t - I 0 t 2

? = B A

? = μ 0 n I A

V R = d ? d t = - μ 0 n A l 0 ( 1 - 2 t )

V R = 0 at   t = 1 2 and I R = V R   Resistance of loop  

 

New answer posted

7 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Magnitude of electric field is constant & the surface is equipotential.

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  Energy     Volume   = M L 2 T - 2 L 3 = M L - 1 T - 2

The distance between two successive bright fringes is fringe width  ( β ) .

β = λ D d = 589 * 10 - 9 * 1.5 0.15 * 10 - 3 = 5.9 m m

New answer posted

7 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Relation between De-Broglie wavelength and K.E. is

λ = h 2 ( K E ) m e λ 1 K E

λ A λ B = K E B K E 1 2 = T A - 1.5 T A T A 2 e V K E B = 2 - 1.5 = 0.5 e V ? B = 4.5 - 0.5 = 4 e V

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