Class 12th

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New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

The dotted ones are s p 2  carbons

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

30 m m o l L - 1 of H C l

Then in 250 m L H C l will be 30 4 m m o l

H 2 S O 4 will be 1 2 * 30 4 m m o l = 98 * 1 2 * 30 4 * 16 - 3 g = 0.3675 g

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

N a C l + K 2 C r 2 O 7 ? H + C r O 2 C l 2 ? N a O H N a 2 C r O 4 ? H 2 O 2 C r O 5 ( C ) H +

  C r O 2 C l 2 5

N a 2 C r O 4 7

C r O 3 6

New question posted

10 months ago

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New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Vapour pressure over solvent is greater than that over solution.

New answer posted

10 months ago

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R
Raj Pandey

Contributor-Level 9

1 f = ( μ - 1 ) 1 R 1 - 1 R 2

R 1 =

R 2 = - 30 c m

1 f = ( 1.5 - 1 ) 1 - 1 - 30

1 f = 0.5 30 f = 60 c m

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Aniline has higher viscosity due to intermolecular H -bonding.

 

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

In strong ligand field C o 3 + will have t 2 g 6 e g 0 of configuration and Δ t = 4 9 Δ 0

New answer posted

10 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Is bulky base, so elimination is dominating.

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