Class 12th
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New answer posted
7 months agoContributor-Level 10
Heat generated in the resistance
H = i²RT
H? = 500 = (1.5)²R (20) ⇒ R = 500/45 = 11.11 Ω
H? = (3)²R (20) = 9 * (500/45) * 20 = 2000 J.
New answer posted
7 months agoContributor-Level 10
Voltage across secondary source
P = V? i? = V? i?
V? = P/i? = 60/0.11 ≈ 545 V
Since voltage across secondary source is more than primary source (220V)
⇒ Step- up transformer.
New answer posted
7 months agoContributor-Level 10
According to Question, we can write
E = λ/ (2πε? r) ⇒ σ = ε? E = λ/ (2πr)
⇒ σ = 8*10? / (2*3.14*3) = 0.424 nCm? ²
New answer posted
7 months agoContributor-Level 10
Using lens maker formula, we can write
1/f = (µ/µ? - 1) (1/R? - 1/R? )
µ = µ? ⇒ 1/f = 0 ⇒ f → Infinite
New answer posted
7 months agoContributor-Level 10
Using de-Broglie equation:
λ = h/p = h/√ (2mK) = h/√ (2meV)
λ ∝ 1/√m
λ? /λ? = √ (m? /m? ) = √ (1.00727/0.00055) = √1831 ≈ 43:1
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