Class 12th

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3 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

3 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

HVZ reaction:

 

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alok kumar singh

Contributor-Level 10

Cannizzaro reaction is shown by aldehydes containing no a–H atoms

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alok kumar singh

Contributor-Level 10

Kindly go through the image

 

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alok kumar singh

Contributor-Level 10

Zn2+ has no unpaired electron and colourless in aqueous solution.

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alok kumar singh

Contributor-Level 10

Homoleptic complexes in which a metal is bound to only one kind of donor groups/ligands.

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alok kumar singh

Contributor-Level 10

In aniline –NH2 is strong activating group due to presence of lone pair in nitrogen.

Aniline does not show Friedel-Craft alkylation reaction, because anhydrous AlCl3 and aniline form salt together

 

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alok kumar singh

Contributor-Level 10

[Ni (H2O)6]2+ Þ Ni2+ is octahedral and [Ni (CN)4]2– is square planar.

In [Ni (H2O)6]2+ Þ Ni2+ has two unpaired electrons and in [Ni (CN)4]2– Þ Ni2+ has no unpaired electrons. [Ni (H2O)6]2+ is coloured as it absorbs red light due to suitable d-d transition and complementary light emitted is green.

[Ni (CN)4]2– has strong field ligand so the electrons of Ni2+ pair up and it is colourless as it cannot absorb light from visible region.

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alok kumar singh

Contributor-Level 10

KCN   + CN

            R – X + KCN  R – CN + KX

            R – X + AgCN  R – NC + AgX

            KCN is ionic therefore ionised and attack occurs through carbon.

            AgCN is covalent therefore attack starts with Nitrogen.

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