Class 12th

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5 months ago

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Vishal Baghel

Contributor-Level 10

from given information : I = A = 60°, r = A 2 = 3 0 ° =>  μ = 3 = c v

v = c 3 t i m e = ( 5 3 1 0 0 ) ( 3 * 1 0 8 3 ) = 5 * 1 0 1 0 s

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

X c = 1 ω c , X L = ω L so at very high frequencies capacitor behaves as conduct and inductor behaves as open circuit. The effective impedance will be 2 Ω .

 

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Payal Gupta

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New answer posted

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Vishal Baghel

Contributor-Level 10

Distance of 4th bright fringe from central maxima = 4 λ D d  

S o , 2 . 4 1 0 0 = 8 λ D d λ = 2 . 4 * 0 . 3 * 1 0 3 1 0 0 * 8 * 1 . 5 = 6 * 1 0 7 m

f = c λ = 3 * 1 0 8 6 * 1 0 7 = 5 * 1 0 1 4 H z

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Payal Gupta

Contributor-Level 10

Ranking in born

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1

Riya

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Trinity

2

Vikash

Cricket

Mansorover

3

Raman

Cricket

Mansorover

4

Kuntala

Chess

Trinity

5

Tamanna

 

St. Stefan

6

Umesh

Football

St. Stefan

7

Shivam

Hockey

St. Stefan

8

Janki

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Trinity

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

Δ M M = Δ μ μ = 2 5 0 5 0 0 = 1 2

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Payal Gupta

Contributor-Level 10

Ranking in born

Name

Game

School

1

Riya

Chess

Trinity

2

Vikash

Cricket

Mansorover

3

Raman

Cricket

Mansorover

4

Kuntala

Chess

Trinity

5

Tamanna

 

St. Stefan

6

Umesh

Football

St. Stefan

7

Shivam

Hockey

St. Stefan

8

Janki

Chess

Trinity

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

Signal bandwidth = 12KHz

No. of station = 6 M H z 1 2 k H z = 5 0 0

New answer posted

5 months ago

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Vishal Baghel

Contributor-Level 10

Using Heat equation : H = i2Rt

=>192 = (4)2 R (1)

H = (8)2 R (5)

=>H = 3840 J

New answer posted

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Payal Gupta

Contributor-Level 10

Ranking in born

Name

Game

School

1

Riya

Chess

Trinity

2

Vikash

Cricket

Mansorover

3

Raman

Cricket

Mansorover

4

Kuntala

Chess

Trinity

5

Tamanna

 

St. Stefan

6

Umesh

Football

St. Stefan

7

Shivam

Hockey

St. Stefan

8

Janki

Chess

Trinity

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