Class 12th

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New answer posted

11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Ranking in born

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Game

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1

Riya

Chess

Trinity

2

Vikash

Cricket

Mansorover

3

Raman

Cricket

Mansorover

4

Kuntala

Chess

Trinity

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Tamanna

 

St. Stefan

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Umesh

Football

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Shivam

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New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

Signal bandwidth = 12KHz

No. of station = 6 M H z 1 2 k H z = 5 0 0

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Using Heat equation : H = i2Rt

=>192 = (4)2 R (1)

H = (8)2 R (5)

=>H = 3840 J

New answer posted

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Ranking in born

Name

Game

School

1

Riya

Chess

Trinity

2

Vikash

Cricket

Mansorover

3

Raman

Cricket

Mansorover

4

Kuntala

Chess

Trinity

5

Tamanna

 

St. Stefan

6

Umesh

Football

St. Stefan

7

Shivam

Hockey

St. Stefan

8

Janki

Chess

Trinity

New answer posted

11 months ago

Five people joined different engineering colleges. Their first names were Komal (Ms.), Mansi (Ms.), Kabeer, Ram and Rupali (Ms.). The surnames were Pandey, Kumar, Verma, Sharma and Gupta. Except for one college which was rated 3 star, all other colleges were rated either 4 star or 5 star.

The “Techno Institute” had a higher rating than college where Rupali studied. The three-star college was not “Decan College”. Ram's last name was Kumar but he didn't study at “Barla College.” Komal, whose last name wasn't Verma, joined “Techno Institute.” Ms. Sharma and Kabeer both studied at four-star colleges. Ms. Pandey studied at t

...more
0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Name

Surname

College

Star

Ram

Kumar

Chemical

4

Komal

Sharma

Techno

4

Rupali

Pandey

Anipal

3

Kabeer

Gupta

Deccan

4

Mansi

Verma

Barla

5

New answer posted

11 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

When electric field is parallel then it would provide zero flux.

New answer posted

11 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Using magnetic field due to straight wire :

B = μ 0 i 4 π r ( s i n α + s i n β )


= 1 0 7 * 1 . 5 ( 0 . 0 9 2 3 ) * ( s i n 6 0 ° + s i n 6 0 ° ) = 1 0 5 T

So, magnetic field due to three wires

= 3 * 10-5 T

inside the plane

New answer posted

11 months ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

d x ( x 1 x + 2 ) 3 / 4 ( x + 2 ) 3 / 4 ( x + 2 ) 5 / 4 = d x ( x 1 x + 2 ) 3 / 4 ( x + 2 ) 2 p u t x 1 x + 2 = t 3 ( x + 2 ) 2 d x = d t

1 3 d t t 3 / 4 = 1 3 . t 1 / 4 1 4 + C = 4 3 ( x 1 x + 2 ) 1 / 4 + C

New answer posted

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Comparing E = 20 cos (2 * 1010 t – 200x) V/m to

E = E 0 c o s ( ω t k x ) v / m              

ω = 2 * 1 0 1 0 , K = 2 0 0               

Speed = 2 * 1 0 1 0 2 0 0 = 1 0 8 m / s  

R.I. = C s p e e d = 3 * 1 0 8 1 0 8 = 3  

N o w R . I . = ε r μ r

3 = ε r * 1

ε r = 9              

            

 

New answer posted

11 months ago

0 Follower 3 Views

J
Jaya Sinha

Beginner-Level 5

Students should prepare complete syllabus when they have time to prepare. However, you can use the list of highweightage chapters in last minute revision for scoring well.

  • The p-Block Elements: This chapter holds a high weightage of 8–10 marks. (in the latest syllabus this is deleted)
  • Aldehydes, Ketones, and Carboxylic Acids: This chapter contributes around 8–10 marks.

  • Biomolecules: This chapter accounts for around 8 marks.

  • Chemical Kinetics: This chapter holds a high weightage of 5-6 marks. 

  • The d- and f-Block Elements: This chapter contributes around 5-6 marks.

  • Amines: This chapter contributes around 5-6 marks.

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