Class 12th

Four married couples competed in a singing competition. Each couple had a unique team name. Points scored by the teams were 2, 4, 6 and 8. The “Sweet Couple” won 2 points. The “Bindas Singers” won two more points than Laxman's team. Mukesh's team won four points more than Lina's team, but Lina's team didn't score the least amount of points. “Just Singing” won 6 points. Waheda wasn't on the team called “New Singers”. Sanjeev's team won 4 points. Divya wasn't on the “Bindas Singers” team. Tapas and Sania were on the same team, but it wasn't the “Sweet Couple.”

The teams arranged in the ascending order of points ar

0 Follower 2 Views

Class 12th Electromagnetic Induction

Contributor-Level 10

As per the given information we have four teams, four couples and 4 different points

I. “Sweet Couple” won 2 points

II. Mukesh's team won 4 points more than Lina's team and Lina's team has not scored the least points. Therefore, only possible options is Lina has 4 points and Mukesh has 8 points. It also means that Mukesh (with point 8) is not with Lina, and both of them does not belongs to “Sweet Couple”

III. “Just Singing” won 6 points. Hence Mukesh and Lina do not belongs to “Just Singing”

IV. Sanjeev's team scored 4 points. While from (II) we have seen that Lina has also 4 points hence Sanjeev and Lina belongs to s

...more

0 0

New answer posted

5 months ago

A square loop of side 20 cm and resistance is moved towards right with a constant speed v₀. The right arm of the loop is in a uniform magnetic field of 5T. The field is perpendicular to the plane of the loop and is going into it. The loop is connected to a network of resistors each of value 4. What should be the value of v₀ so that a steady current of 2 mA flows in the loop

0 Follower 6 Views

alok kumar singh

Contributor-Level 10

$l = \frac{V_{0} B l}{R} = \frac{V_{0} * 5 * 20 * 1 0^{- 2}}{4 + 1}$

$2 * 1 0^{- 3} = V_{0} * 20 * 1 0^{- 2}$

$V_{0} = \frac{2 * 1 0^{- 3}}{20 * 1 0^{- 2}} = \frac{2}{2} * 1 0^{- 2} = 1 * 1 0^{- 2} m / s$

V₀ = 1 cm/s

0 0

New answer posted

5 months ago

Directions for questions: Read the information carefully and answer the questions given below.

0 Follower 1 View

Contributor-Level 10

As per the given information we have four teams, four couples and 4 different points

I. “Sweet Couple” won 2 points

III. “Just Singing” won 6 points. Hence Mukesh and Lina do not belongs to “Just Singing”

IV. Sanjeev's team scored 4 points. While from (II) we have seen that Lina has also 4 points hence Sanjeev and Lina belongs to s

...more

0 0

New answer posted

5 months ago

Read the information carefully and answer the questions given below.

Bus route no. 971 has exactly six stops on its route. Any bus plying on this route starts from the initial position, then stops first at stop one and then stops at two, three, four, five, and six respectively. After the bus reaches stop six, the bus turns and returns to its initial position and repeats the cycle. Buses are not allowed to carry people on its return journey.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made regarding the stops on this

0 Follower 1 View

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh	Rajghat		Peetampura	Kanpur	Lokhand wala	Saket Xingh
Stop 1	Stop 2		Stop 3	Stop 4	Stop 5	Stop 6
Case II:
Kanpur	Lokhand wala	Peetampura		Aligarh	Rajghat	Saket Xingh
Stop 1	Stop 2	Stop 3		Stop 4	Stop 5	Stop 6

0 0

New answer posted

5 months ago

Class 12th Maths

Let f be a non-negative function in [0, 1] and twice differentiable in (0, 1). If $\int_{0}^{x} \sqrt[]{1 - {(f (t))}^{2}} d t = \int_{0}^{x} f (t) d t,$ and f(0) = 0, then $\underset{x \to 0}{l i m} \frac{1}{x^{2}} \int_{0}^{x} f (t) d t :$

0 Follower 7 Views

Raj Pandey

Contributor-Level 9

Applying Leibniz theorem,

$\sqrt[]{1 - {(f' (x))}^{2}} = f (x) \Rightarrow \frac{f' (x)}{\sqrt[]{1 - {(f (x))}^{2}}} = 1$ on integrating both sides, we get

$f (x) = s i n x + C$ put x = 0 and f (0) = 0 we get C = 0

$N o w \underset{x \to 0}{l i m} \frac{\int_{0}^{x} f (t) d t}{x^{2}}, (\frac{0}{0})$ by L' Hospital rule $\underset{x \to 0}{l i m} \frac{f (x)}{2 x} = \underset{x \to 0}{l i m} \frac{s i n x}{2 x} = \frac{1}{2}$

0 0

New answer posted

5 months ago

Read the information carefully and answer the questions given below.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made regarding the stops on this

0 Follower 1 View

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh	Rajghat		Peetampura	Kanpur	Lokhand wala	Saket Xingh
Stop 1	Stop 2		Stop 3	Stop 4	Stop 5	Stop 6
Case II:
Kanpur	Lokhand wala	Peetampura		Aligarh	Rajghat	Saket Xingh
Stop 1	Stop 2	Stop 3		Stop 4	Stop 5	Stop 6

0 0

New answer posted

5 months ago

Read the information carefully and answer the questions given below.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made regarding the stops on this

0 Follower 1 View

Contributor-Level 10

Following is the structure of the stops on this route:

Case I:

Aligarh	Rajghat		Peetampura	Kanpur	Lokhand wala	Saket Xingh
Stop 1	Stop 2		Stop 3	Stop 4	Stop 5	Stop 6
Case II:
Kanpur	Lokhand wala	Peetampura		Aligarh	Rajghat	Saket Xingh
Stop 1	Stop 2	Stop 3		Stop 4	Stop 5	Stop 6

0 0

New answer posted

5 months ago

Directions for questions: Read the information carefully and answer the questions given below.

Following are the six stops – Lokhand Wala, Saket Xing, Kanpur, Aligarh, Peetampura, and Rajghat in no particular order, Further, following observations have been made re

0 Follower 1 View