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Class 12th English

N1, N2, N3, N4, N5, N6, N7 and N8 are eight reference books to be kept on three shelves: lowest, middle or top. The reference books are of four different subjects: Physics, Chemistry, Biology and History two reference books of each subject. No two reference books of same subject are kept on one shelf. Also

I. N1 is above N4 ; N7 is below N2 ; N5 is below N6 and N8 is below N3.

II. Top shelf has no Biology's reference books; middle shelf has no Physics' reference books and lowest shelf has no Chemistry's reference books.

III. N5 and History's reference books are not together; N8 and Chemistry's reference books are not together; N6

...more

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Payal Gupta

Contributor-Level 10

Please find the answer below

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New answer posted

5 months ago

Class 12th English

Directions for questions: Read the information carefully and answer the questions given below.

I. N1 is above N4 ; N7 is below N2 ; N5 is below N6 and N8 is below N3.

II. Top shelf has no Biology's reference books; middle shelf has no Physics' reference books and lowest shelf has no Chemistry's reference books.

III. N5 and

...more

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Payal Gupta

Contributor-Level 10

(N4, N7, N5, N8) will be in middle or the lowest shelf.

Note that any reference book of one subject can be absent from only one shelf.

N2 and Biology reference book are not on one shelf

N2 is on top shelf.

Similarly N6 and N8 are on middle and the lowest shelves respectively.

N5 and History reference book are not on one shelf and N5 is in middle or the lowest shelf One of these shelves will also not have History reference book and that shelf will only have two reference book.

we can have two different arrangements:

Reference book Subject

N1, N2, N3 ? Physics, Chemistry, H

...more

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5 months ago

Class 12th Electromagnetic Induction

A constant magnetic field of 1T is applied in the x > 0 region. A metallic circular ring of radius 1m is moving with a constant velocity of 1 m/s along the x-axis. At t = 0, the centre of O of the ring is at x = -1m. What will be the value of the induced emf in the ring at t = 1s? (Assume the velocity of the ring does not change.)

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alok kumar singh

Contributor-Level 10

$ε = B v (2 R) = 1 * 1 * 2 * 1 = 2 V$

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Class 12th Physics

Figure shows a rod AB, which is bent in a 120° circular arc of radius R. A charge (-Q) is uniformly distributed over rod AB. What is the electric field $\vec{E}$ at the centre of curvature O?

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alok kumar singh

Contributor-Level 10

$λ = \frac{- Q}{R * 2 π / 3}$

$\vec{E} = \frac{2 k λ}{R} s i n (\frac{θ}{2}) (- \hat{i})$

$\Rightarrow \vec{E} = \frac{2 k}{R} * \frac{- 3 Q}{2 π R} s i n 60 ° (- \hat{i})$

$\Rightarrow \vec{E} = \frac{3 \sqrt[]{3} Q}{8 π^{2} ε_{0} R^{2}} (\hat{i})$

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Class 12th Dual Nature of Radiation and Matter

A monochromatic neon lamp with wavelength of 670.5nm illuminates a photo-sensitive material which has a stopping voltage of 0.48V. What will be the stopping voltage if the source light is changed with another source of wavelength of 474.6nm?

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alok kumar singh

Contributor-Level 10

$e V_{S 2} = \frac{h c}{λ_{1}} - ?$

$e V_{S 2} = \frac{h c}{λ_{2}} - ?$

$e V_{S 2} - e V_{S 1} = \frac{h c}{λ_{2}} - \frac{h c}{λ_{1}}$

$\Rightarrow V_{S 2} = 0.48 + 12.43 * 1 0^{- 7} * (\frac{1}{474.6} - \frac{1}{670.5}) * 1 0^{- 9}$

= 1.25 V

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Class 12th Physics Ray Optics and Optical Instruments

Find the distance of the image from object O, formed by the combination of lenses in the figure:

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Vishal Baghel

Contributor-Level 10

$\frac{1}{V_{1}} + \frac{1}{30} = \frac{1}{10}$

V₁ = 15 cm

$\frac{1}{V_{2}} - \frac{1}{10} = - \frac{1}{10}$

$\Rightarrow V_{2} = \infty$

$\Rightarrow V_{3} = 30 c m$

$\Rightarrow O V_{3} = 75 c m$

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Class 12th Physics

For a transistor a and b are given as $α = \frac{I_{C}}{I_{E}} a n d β = \frac{I_{C}}{I_{B}} .$ Then the correct relation between a and b will be:

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alok kumar singh

Contributor-Level 10

β $= \frac{I_{C}}{I_{E}} = \frac{I_{C}}{I_{E} - I_{C}} = \frac{I_{C} / I_{E}}{1 - l_{C} / I_{E}} = \frac{α}{1 - α}$

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Class 12th Physics

For full scale deflection of total 50 divisions, 50 mV voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is 2 div/mA will be:

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alok kumar singh

Contributor-Level 10

Current at full deflection,

$l_{m a x} = \frac{50}{2} = 25 m A$

$R = \frac{V}{l_{m a x}} = \frac{50}{25} = 2 K Ω$

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Class 12th Electromagnetic Waves

Electric field in a plane electromagnetic wave is given by

E = 50 sin(500x – 10 * 10¹⁰t) V/m

The velocity of electromagnetic wave in this medium is:

(Given C = speed of light in vacuum)

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Vishal Baghel

Contributor-Level 10

$V = \frac{c o e f f i c i e n t o f t i m e}{c o e f f i c i e n t o f x} = \frac{ω}{k}$

$\Rightarrow V = \frac{10 * 1 0^{10}}{500} = 2 * 1 0^{8} = \frac{2 * c}{3}$

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Class 12th Physics

For a transistor in CE mode to be used as an amplifier, it must be operated in:

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Vishal Baghel

Contributor-Level 10

Active region of the CE transistor is linear region and is best suited for its use as an amplifier.

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