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5 months ago

Class 12th English

The following table shows the highest and the average marks obtained by students in subjects over the year. The maximum mark in each subject is 100.

SUBJECTS
	Botany		Economics		Physics		Chemistry		Zoology
	High	Average	High	Average	High	Average	High	Average	High	Average
2001	85	62	75	52	98	65	88	72	72	46
2002	80	70	80	53	94	60	89	70	70	55
2003	82	65	77	54	85	62	95	64	64	58
2004	71	56	84	65	92	68	97	68	68	49
2005	75	52	82	66	91	64	92	75	75	58
2006	82	66	81	57	89	66	98	72	72	62

The average highest marks in English in 2001, 2002 and 2005 were exactly equal to the highest marks in Hindi in which of the following years?

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

Average the highest marks

$\frac{85 + 80 + 75}{3} = \frac{240}{3} = 80$

Therefore, the correct answer is option (d)

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New answer posted

5 months ago

Class 12th English

The following table shows the highest and the average marks obtained by students in subjects over the year. The maximum mark in each subject is 100.

SUBJECTS
	Botany		Economics		Physics		Chemistry		Zoology
	High	Average	High	Average	High	Average	High	Average	High	Average
2001	85	62	75	52	98	65	88	72	72	46
2002	80	70	80	53	94	60	89	70	70	55
2003	82	65	77	54	85	62	95	64	64	58
2004	71	56	84	65	92	68	97	68	68	49
2005	75	52	82	66	91	64	92	75	75	58
2006	82	66	81	57	89	66	98	72	72	62

What was the approximate percentage increase in average marks in History from 2001 and 2002?

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

Percentage Increase $\frac{55 - 46}{46} * 100 = 20 %$

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New answer posted

5 months ago

Class 12th English

The following table shows the highest and the average marks obtained by students in subjects over the year. The maximum mark in each subject is 100.

SUBJECTS
	Botany		Economics		Physics		Chemistry		Zoology
	High	Average	High	Average	High	Average	High	Average	High	Average
2001	85	62	75	52	98	65	88	72	72	46
2002	80	70	80	53	94	60	89	70	70	55
2003	82	65	77	54	85	62	95	64	64	58
2004	71	56	84	65	92	68	97	68	68	49
2005	75	52	82	66	91	64	92	75	75	58
2006	82	66	81	57	89	66	98	72	72	62

The difference in the average marks in History between 2003 and 2004 was exactly equal to the difference in the highest marks in Hindi between which of the following pair of years?

0 Follower 1 View

Payal Gupta

Contributor-Level 10

The difference is 9. Therefore the correct answer is option (a)

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New answer posted

5 months ago

Class 12th English

Direction for question: Rea refer to the following table and solve the questions based on it.

The following table shows the highest and the average marks obtained by students in subjects over the year. The maximum mark in each subject is 100.

SUBJECTS
	Botany		Economics		Physics		Chemistry		Zoology
	High	Average	High	Average	High	Average	High	Average	High	Average
2001	85	62	75	52	98	65	88	72	72	46
2002	80	70	80	53	94	60	89	70	70	55
2003	82	65	77	54	85	62	95	64	64	58
2004	71	56	84	65	92	68	97	68	68	49
2005	75	52	82	66	91	64	92	75	75	58
2006	82	66	81	57	89	66	98	72	72	62

What were the grand average marks of the five subjects in 2005?

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

$A v e r a g e = \frac{52 + 66 + 64 + 75 + 58}{5} = \frac{315}{5} = 63$

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New answer posted

5 months ago

Class 12th English

The XYZ manufacturing company produces a product which has 6 month demand cycle as given below:

Month	Demand in Units	Working days/month
January	600	22
February	1000	19
March	800	21
April	200	21
May	400	22
June	600	2

Company's policy is to retain safety stock of 20% of monthly demand and each month's safety stock becomes the opening stock for the next month, and opening stock for January is 100 units. Each unit requires 10 labour-hours and company works 8 hour/day.

If there are currently 20 workers employed, and how many worker are needed to be laid off in January to accommodate demand?

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

Please find the answer below

0 0

New answer posted

5 months ago

Class 12th Chemistry Electrochemistry

A solution of Fe₂(SO₄)₃ is electrolyzed for 'x' min with a current of 1.5 A to deposit 0.3482g of Fe. The value of x is ______. [nearest integer]

Given : 1F = 96500 C mol1

Atomic mass of Fe = 56 g mol1

0 Follower 5 Views

Raj Pandey

Contributor-Level 9

$F e^{+ 3} + 3 e^{-} \to F e$

3 Faraday is required to deposit 1 mole Fe

$? 56 g$ deposited by $3 * 96500$ C charge

$∴ 0.3482 g$ deposited by $\frac{3 * 96500}{56} * 0.3482 C = \frac{100803.9}{56} C = 1800.7 C$

$∴ Q = I t$

1800.07 = 1.5 t

$∴ t = 1200 s e c = \frac{1200}{60}$ min = 20 min

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New answer posted

5 months ago

Class 12th English

The XYZ manufacturing company produces a product which has 6 month demand cycle as given below:

Month	Demand in Units	Working days/month
January	600	22
February	1000	19
March	800	21
April	200	21
May	400	22
June	600	2

In which month production requirement is highest?

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

Please find the answer below

0 0

New answer posted

5 months ago

Class 12th English

Direction for question: Go through the table given below and solve the questions based on it.

The XYZ manufacturing company produces a product which has 6 month demand cycle as given below:

Month	Demand in Units	Working days/month
January	600	22
February	1000	19
March	800	21
April	200	21
May	400	22
June	600	2

What is the opening stock for June?

0 Follower 1 View

Payal Gupta

Contributor-Level 10

Month	Opening	Demand	Resource 20%	Production	Working days
January	100	600	120	620	22
February	120	1000	200	1080	19
March	200	800	160	760	21
April	160	200	40	80	21
May	40	400	80	440	22
June	80	600	120	640	20

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New answer posted

5 months ago

Class 12th Chemistry Chemical Kinetics

At 345 K, the half life for the decomposition of a sample of a gaseous compound initially at 55.5 kPa was 340s. When the pressure was 27.8 kPa., the half life was found to be 170s. The order of the reaction is ________. [integer answer]

0 Follower 3 Views

Raj Pandey

Contributor-Level 9

t1/2 = 340 secP0 = 55.5 kPa

t1/2 = 170 sec P0 = 27.8 kPa

$∴ t_{1 / 2} \propto {(P_{0})}^{1 - n}$

$∴ 1 - n = 1 n = 0$

$∴$ zero order reaction

0 0

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