Class 12th

Contributor-Level 10

This is a Assertion and Reason Type as classified in NCERT Exemplar

Ans: Correct Option: (iii)

(i)The electrode potential of Cu²⁺/Cu is negative. The electrode potential of 2H⁺/H²is 0.00V. Therefore, the assertion is correct and the reason is incorrect and the reason is not a correct explanation of assertion. Therefore, this option is incorrect

(ii) E $°$ Cu²⁺/Cu is not negative so the reason is incorrect. Therefore, this option is incorrect

(iii) The electrode potential of Cu²⁺/Cu is negative. The electrode potential of 2H⁺/H² is 0.00V. Therefore, the assertion is correct and the reason is incorrect. Therefore, this opt

...more

This is a Assertion and Reason Type as classified in NCERT Exemplar

Ans: Correct Option: (iii)

(ii) E $°$ Cu²⁺/Cu is not negative so the reason is incorrect. Therefore, this option is incorrect

(iii) The electrode potential of Cu²⁺/Cu is negative. The electrode potential of 2H⁺/H² is 0.00V. Therefore, the assertion is correct and the reason is incorrect. Therefore, this option is correct

(iv) Assertion is true and the reason is false therefore this option is incorrect

(v)Assertion is true therefore this option is incorrect.

less

0 0

New answer posted

7 months ago

Match the items of Column I and Column II.

0 Follower 3 Views

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Three

Contributor-Level 10

This is a Matching Type Question as classified in NCERT Exemplar

(i)- (b) ; (ii)- (a) ; (iii)- (d); (iv)- (c)

The rate rule was discovered experimentally and can be used to predict the reaction rate and reactant concentrations.

The rate constant is the proportionality constant that describes the relationship between the molar concentration of the reactants and the rate of a chemical reaction.

The rate constant (k) of a reaction is proportional to its temperature, i.e., for a given reaction at a given temperature, the rate constant (k) is constant.

The order of a reaction is a quantity that has been empirically determined. As a result

...more

0 0

New answer posted

7 months ago

Match the items of Column I and Column II based on data given below:

Column I	Column II
(i)F₂	(a)metal is the strongest reducing agent
(ii)Li	(b)metal ion which is the weakest oxidizing agent
(iii)Au ³⁺	(c)non-metal which is the best oxidizing agent
(iv)Br ⁻	(d)unreactive metal
(v)Au	(e)anion that can be oxidized by Au ³⁺
(vi)Li⁺	(f)anion which is the weakest reducing agent
(vii)F⁻	(g)metal which is an oxidising agent

E $\frac{G}{R}$ _F2/F=2.87V E $\frac{K}{C}$ _Li/Li= 3.5V E_Au3+/Au = 1.4V E $\frac{Λ m}{Λ^{0} m}$ _Br2/Br^- = 1.09V

0 Follower 3 Views

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) F₂is a non-metal which is the best oxidizing agent since the standard reduction potential of F₂ is 2.87V.

(ii)Liis a metal and the strongest reducing agent because the standard reduction potential of Li is −3.05V.

(iii)Au³⁺is a metal ion which is an oxidizing agent as standard reduction potential of Au³⁺ is 1.40V.

(iv) Br⁻is an anion that can be oxidized by Au³⁺ as standard reduction potential of Au³⁺is 1.40V which is more than that of Br⁻ which is E $Q$ _Br2/Br−0=1.09V.

(v)Auis an unreactive metal

(vi)Li⁺ is a metal ion having the least value

...more

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) F₂is a non-metal which is the best oxidizing agent since the standard reduction potential of F₂ is 2.87V.

(ii)Liis a metal and the strongest reducing agent because the standard reduction potential of Li is −3.05V.

(iii)Au³⁺is a metal ion which is an oxidizing agent as standard reduction potential of Au³⁺ is 1.40V.

(iv) Br⁻is an anion that can be oxidized by Au³⁺ as standard reduction potential of Au³⁺is 1.40V which is more than that of Br⁻ which is E $Q$ _Br2/Br−0=1.09V.

(v)Auis an unreactive metal

(vi)Li⁺ is a metal ion having the least value of standard reduction potential of 3.05V. Hence it is the weakest oxidizing agent

(vii)F⁻is an anion that is the weakest reducing agent as it has less oxidation potential.

Hence, the answer is:

(i)-c; (ii)-a; (iii)-g; (iv)-e; (v)-d; (vi)-b; (vii)-f

less

0 0

New answer posted

7 months ago

Match the items of Column I and Column II.

0 Follower 4 Views

Contributor-Level 10

This is a Matching Type Question as classified in NCERT Exemplar

(i)- (b) ; (ii)- (c) ; (iii)- (a)

The rate of conversion in diamond is normally imperceptible.

Long-term rate at a moment's notice

The average rate is only for a short time.

0 0

New answer posted

7 months ago

Class 12th Electrochemistry

Match the items of column I and column II

Column I	Column II
(i)Lechlanche cell	(a)cell reaction
(ii)Ni−Cd	(b) does not involve any ion in solution and is used in hearing aids.
(iii)Fuel cell	(c)rechargeable
(iv)Mercury cell	(d)reaction at anode
	(e) converts energy of combustion into electrical energy

0 Follower 4 Views

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i)The reaction occurring at Lechlanche cells are

At anode: Zn→Zn²⁺ + 2e⁻

At cathode: MnO₂ + NH₄⁺+ e⁻→MnO (OH)+NH₃

(ii)Ni−Cd is rechargeable. So it has a longer lifetime.

(iii) Energy in the fuel cell is due to the combustion process. It converts combustion energy into electrical energy 2H₂ + O₂→2H₂O

(iv) Mercury cells don't involve any solution and are used in hearing aids.

Hence, the answer is:

(i)-d; (ii)-c; (iii)-a, e; (iv)-b

0 0

New answer posted

7 months ago

Match the statements given in Column I and Column II

0 Follower 28 Views

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Three

Contributor-Level 10

This is a Matching Type Question as classified in NCERT Exemplar

(i)- (c) ; (ii)- (a) ; (iii)- (d); (iv)- (f); (v)- (b); (vi)- (b)

A catalyst can influence the rate of a process by lowering the activation energy

When it comes to molecularity, there can't be a fraction or a zero.

The second half life of a first order reaction is the same as the first.

Activation energy refers to the percentage of molecules with an energy equal to or greater than activation energy.

Correct orientation is not always present when it comes to energetically favourable activities.

Because the area under the Maxwell Boltzmann curve is constant, the total probability

...more

0 0

New answer posted

7 months ago

Match the terms given in Column I with the units given in Column II.

Column I	Column II
(i)k	*(a)I x T***
(ii)Λ_m	(b) $\frac{Λ m}{Λ^{0} m}$
(iii) $α$	(c) $\frac{K}{C}$
(iv) $Q$	(d) $\frac{G}{R}$

0 Follower 2 Views

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i)Conductivity k is defined as k = $°$

(ii)Molar conductivity is given by Λ_m = $* T$

(iii)Degree of dissociation is given by $\frac{Λ m}{Λ^{0} m}$ ? = $α$

(iv)Charge $\frac{K}{C}$ is the product of current and time $Q$ = I $\frac{G}{R}$

Hence, the answer is:

(i)-d; (ii)-c; (iii)-b; (iv)-a

0 0

New answer posted

7 months ago

Match the graph given in Column I with the order of reaction given in Column II. More than one item in Column I may link to the same item of Column II.

0 Follower 11 Views

Contributor-Level 10

This is a Matching Type Question as classified in NCERT Exemplar

(i)- (a) ; (ii)- (b) ; (iii)- (b); (iv)- (a)

A zero-order reaction is one in which the reactant concentrations do not change over time and the rate of concentration remains constant.

A first-order reaction is one in which the rate of the reaction is linearly proportional to the concentration of only one ingredient. In other terms, a first-order reaction is a chemical reaction whose rate is determined by changes in only one of the reactants' concentration.

0 0

New answer posted

7 months ago

Class 12th Electrochemistry

Match the terms given in Column I with the units given in Column II.

Column I	Column II
(i)Lead storage battery	(a)Maximum efficiency
(ii)Mercury cell	(b)prevented by galvanization
(iii)Fuel cell	(c)gives steady potential
(iv)Rusting	(d)Pbis the anode,PbO₂ is cathode

0 Follower 2 Views

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Three

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) The cell reaction of a lead storage battery is as follows;

Pb + PbO₂+ 2H₂SO₄→2H₂SO₄+ 2H₂O

At cathode:PbO₂ (s)+SO₄²⁻ (aq)+2e⁻→2PbSO₄ (s) + 2H₂O (l)

At anode:Pb (s)+SO₄²⁻ (aq)→PbSO₄ (s)+2e⁻

Therefore Pb is the anode and PbO₂ is cathode

(ii)Mercury cell doesn't contain ions so it gives steady potential.

(iii)Fuel cells have maximum efficiency as they produce energy due to the combustion reaction of fuel.

(iv)Rusting is prevented by galvanization.

Hence, the answer is:

(i)-d ; (ii)-c ; (iii)-a ; (iv)-b

0 0

New answer posted

7 months ago

Match the terms given in Column I with the units given in Column II.

Column I	Column II
(i) Λm	(a)intensive property
(ii) E_cell	(b)depends on the number of ions/volume
(iii) k	(c)extensive property
(iv) ΔrG_cell	increases with dilution

0 Follower 3 Views