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a year ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- In Biot-Savart's law, magnetic field B is parallel (II) to id * r and idl have its direction along the direction of flow of current.

Here, for the direction of magnetic field, At dl2, located at (0, R,0) due to wire d1 is given by B I | dl * r or I *j (because point (0, R,0)lies on y-axis), but I * j= k

So, the direction of magnetic field at d2 is along z-direction.

The direction of magnetic force exerted at d2 because of the first wire along the x-axis

F =i (l * B) i.e., F| (i *k ) or along− j direction.

Therefore, force due to dl1 on

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New answer posted

a year ago

0 Follower 22 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- considering magnetic field along B=Bk and electron enters with a velocity v=vi into a cubical region

The force on electron using Lorentz force = -e (vi * Bk)= evBi

So the force F= -eE0 k accelerates along z axis which in turn increases the radius of circular path and hence particle transversed on spiral path.

New answer posted

a year ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- for a charge particle to move in circular path

Mv2/r = qvB

v/r=w= bq/m

w= v/r = LT-1L = T-1

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- general formula for magnetic field at center is

B= μ0I4πr (θ)

B1= μ0I4πrπ2=μ0I8r k for xy plane

B2= μ0I8r i for zy plane

B3= μ0I8r j for xz plane

After joining together B= μ0I8πr  (i+j+k)

New answer posted

a year ago

0 Follower 17 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation – in biot savart law, magnetic field B is parallel to idlr and idl have its direction along the direction of flow of current.

Here, for the direction of magnetic field at O2, due to wire carrying I1 current is B| parallel idl * r or I * k, but it is -j

So the direction at O2 is along y-direction.

The direction of magnetic force exerted at O2 because of the wire along x-axis

F= ilB=j (-j)=0

So the force is zero.

New answer posted

a year ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

No, the potential function have no free space because when there is a free space there will be a leakage of potential at that point.

New answer posted

a year ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation – here, the condition of magnetic resonance is violated.

When the frequency of radio frequency field were doubled, the time period of the radio frequency field were halved. Therefore, the duration in which particle completes half revolution inside the dees, radio frequency completes the cycle.

Hence, particle will accelerate and decelerate alternatively. So the radius of path in the dees will remain same.

New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

It is only possible when their sizes are different . when their sizes are different there capacity would change. So there is potential difference btween them.

New question posted

a year ago

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New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- yes, the magnetic force differ from inertial frame to frame. The magnetic force is frame dependent.

The net acceleration which comes into existing out of this is however, frame independent for inertial frames.

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