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Communication Systems Class 12th

Given below are two statements:

Statement I : A speech signal of 2 kHz is used to modulate a carrier signal of 1 MHz. The bandwidth.

Statement II : The side band frequencies are 1002 kHz and 998 kHz.

In the light of the above statements, choose the correct answer from the options given below:

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a month ago

Communication Systems Class 12th

What should be the height of transmitting antenna and the population covered if the televition telecast is to cover a radius of 150 km? The average population density around the tower is 200 / km² and the value of R_e = 6.5 * 10⁶ m.

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Vishal Baghel

Contributor-Level 10

d = 150 km

$d = \sqrt[]{2 h R}$

$h = \frac{d^{2}}{2 R} = \frac{{(150 * 1 0^{3})}^{2}}{2 * 6.5 * 1 0^{6}} = 1731 m .$

Population covered

$π r^{2} * σ = 3.14 * 15 0^{2} * 2000 = 1413 * 1 0^{5}$

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Communication Systems Class 12th

A bandwidth of 6 MHz is available for A.M. transmission. If the maximum audio signal frequency used for modulating the carrier wave is not to exceed 6 kHz. The number of stations that can be broadcasted within this band simultaneously without interfering with each other will be_______.

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Vishal Baghel

Contributor-Level 10

Signal bandwidth = 12KHz

No. of station = $\frac{6 M H z}{12 k H z} = 500$

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2 months ago

Communication Systems Class 12th

A transmitting antenna has a height of 320 m and that of receiving antenna is 2000m. The maximum distance between them for satisfactory communication in line of sight mode is 'd'. The value of 'd' is……….km.

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Vishal Baghel

Contributor-Level 10

$d = \sqrt[]{2 R h_{T}} + \sqrt[]{2 R h_{R}}$

$\Rightarrow d m = (\sqrt[]{2 * 6400 * 1 0^{3} * 320} + \sqrt[]{2 * 6400 * 1 0^{3} * 2000})$

= 224 km

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2 months ago

Communication Systems Class 12th

An amplitude modulated wave is represented by $C_{m} (t) = 10 (1 + 0.2 c o s 12560 t) s i n (111 * 1 0^{4} t) v o l t s .$

The modulating frequency in kHz will be……. .

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Vishal Baghel

Contributor-Level 10

$ω_{m o d u l a t i o n} = 2 π f_{m o d u l a t i o n}$

$f_{m o d u l a t i o n} = \frac{ω_{m o d u l a t i o n}}{2 π}$

$= \frac{12560}{2 π}$

= 2000 Hz

= 2kHz

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2 months ago

Communication Systems Class 12th

A signal of 100 THz frequency can be transmitted with maximum efficiency by:

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Vishal Baghel

Contributor-Level 10

Optical fibre frequency range is 1 THz to 1000 THz.

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2 months ago

Communication Systems Class 12th

The height of a transmitting antenna at the top of a tower is 25m and that of receiving antenna is, 49m. The maximum distance between them, for satisfactory communication is LOS (Line-Of-Sight) is $K \sqrt[]{5} * 1 0^{2} m .$ The value of K is___________.

(Assume radius of Earth is 64 * 10⁺⁵m) [Calculate upto nearest integer value]

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Vishal Baghel

Contributor-Level 10

Given, hT = 25m, R = 6400 km

hR = 49m

dm (Maximum distance for satisfactory communication)

dm = $\sqrt[]{2 R h_{T}} + \sqrt[]{2 R h_{R}}$ $_{}_{}$

dm = $\sqrt[]{2 * 6400 * 1 0^{3} * 25} + \sqrt[]{2 * 6400 * 1 0^{3} * 49}$ $^{}^{}$

= $\sqrt[]{5 * 1 0^{4} * 6400} + \sqrt[]{6400 * 1 0^{3} * 49 * 2}$ $^{}^{}$

= $192 \sqrt[]{5} * 1 0^{2}$ $^{}$

= $k \sqrt[]{5} * 1 0^{2}$ $^{}$

k= 192

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2 months ago

Communication Systems Class 12th

In the case of amplitude modulation to avoid distortion the modulation index $(μ)$ should be:

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Vishal Baghel

Contributor-Level 10

Based on Theoretical data (modulation index, $μ \leq 1)$

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2 months ago

Communication Systems Class 12th

The required height of a TV tower which can cover the population of 6.03 lakh is h. If the average population density is 100 per square km and the radius of earth is 6400 km, then the value of h will be ________ m.

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Vishal Baghel

Contributor-Level 10

$d = \sqrt[]{2 R h}$

$d = \sqrt[]{2 * 6400 * h * 1 0^{- 3}} (h i n m)$

Area = $π d^{2}$

$= (π * 2 * 6400 * h * 1 0^{- 3})$ km²

h = 150m

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2 months ago

Communication Systems Physics NCERT Exemplar Solutions Class 12th Chapter Fifteen

Choose the correct statement for amplitude modulation

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Payal Gupta

Contributor-Level 10

In amplitude modulation, the amplitude of the career signal is varied in according with the modulating signal.

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