Communication Systems

Get insights from 65 questions on Communication Systems, answered by students, alumni, and experts. You may also ask and answer any question you like about Communication Systems

Follow Ask Question
65

Questions

0

Discussions

3

Active Users

0

Followers

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- it is represented by a diagram given below

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- Here, in this question, the frequency of modulated signal received becomes more, which is possible with the poor bandwidth selection of amplifiers.

This happens because bandwidth in amplitude modulation is equal to twice the

Frequency of modulating signal. But, the frequency of male voice is less than that of a female.

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- c

Explanation- The device which follows square law is used for modulation purpose. Characteristics shown by (i) and (iii) corresponds to linear devices.

Characteristics shown by (ii) corresponds to square law device. Some part of (i) also

Follow square law.

Hence, (ii)and (iv) can be used for modulation.

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation- frequency of career wave and frequency of amplitude modulated wave is same which is wc .

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a

Frequency of career signal = 1MHz and frequency = 3KHz= 0.003MHz

So frequency of side bands = 1 ? 0.003

So 1.003MHz and 0.997MHz

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer-b

p = 1kW= 1000W

Attenuation of signal = -2dB/km and total path length = 5km

Gain in dB= 5 * - 2 = - 10 d B

Gain in dB= 10 log (p0/pi)……. (i)

-10=10 log (p0/pi)= -10log (pi/po)

logPi/po=1 = log (pi/po)= log10

pi/p0=10= 1000W= 10p0

p0=100W

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- a

length of building is given by l= 500m

And λ ~ 4l= 4 *  100 =400mf

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Ground wave propagation – 530KHz to 1710KHz

Sky wave propagation- 1710KHz- 40MHz

Space wave propagation- 54MHz to 42GHz 

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

This is a  Short Answer Type Questions as classified in NCERT Exemplar

In amplitude modulated wave side frequency contain the information and from the question the power will be ωc, (ωc – ωm) and (ωc + ωm)

So to minimise cost of radiation we use both (ωc – ωm) and (ωc + ωm)

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Frequency, fmax= 9 (Nmax)1/2

For F1 layer frequency is 5MHz

So 5 * 10 6 = 9 ( N m a x ) 1/2

Nmax= (5/9 * 10 6 )2= 3.086 * 1011/m3

For F2 layer 8MHz

8 * 10 6 = 9 ( N m a x ) 1/2

Nmax= (8/9 * 10 6 )2= 7.9 * 1011/m3

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 681k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.