Coordination Compounds

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a month ago

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V
Vishal Baghel

Contributor-Level 10

Number of GI in [Co (NH? )? (NO? )? ] is 2 i.e, X
Number of GI in [Cr (C? O? )? ]³? is 0 i.e. Y
[X + Y] = 2

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

(CH?)?N?HCl produces H? which reacts with NaHCO? and CO? gas evolved, because HCl is stronger acid than H?CO?

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a month ago

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Vishal Baghel

Contributor-Level 10

[MnCl? ]³?
Mn (25) → [Ar] 4s²3d?
Cl? → weak ligand
Mn³? → 3d? i.e. t? g³, eg¹
Hybridization → sp³d² and paramagnetic

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a month ago

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Vishal Baghel

Contributor-Level 10

(A) [PtCl? (NH? )? ], Number of GI = 2


(B) [Ni (CO)? ], Number of G.I = 0 as it is tetrahedral.
(C) [Ru (H? O)? Cl? ] Number of G.I = 2 (Facial and Meridional)


(D) [CoCl? (NH? )? ]? Number of G.I = 2 (Cis and trans)

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a month ago

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

a month ago

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

In strong field of octahedral complex of Fe2+, the electronic configuration is,

F e 2 6 2 + [ A r ] 3 d 6 4 s 0

Number of unpaired electrons are zero in the presence of strong field ligand.

Hence, spin only magnetic moment = n ( n + 2 ) = 0 B M ( n = 0 )

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2 months ago

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Vishal Baghel

Contributor-Level 10

[ F e ( C O ) 4 ( C 2 O 4 ) ] +

x + 4 * 0 – 2 * 1 = +1

x = +3

Fe+3 = 4s0 3d5

In presence of strong ligand, i.e, CO.

Spin only magnetic moment

= n ( n + 2 ) B . M = 1 ( 1 + 2 ) B . M

3 B . M . = 1 . 7 3 B . M

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

A g + ( a q ) + 2 N H 3 ( a q ) ? A g ( N H 3 ) 2 + ( a q )

t = 00.8 M ( a 2 ) M                  

0 =   5 * 10-8 M   ( a 2 1 . 6 ) M   0.8M

k f = [ A g ( N H 3 ) 2 + ] [ A g + ] [ N H 3 ] 2

1 0 8 = 0 . 8 ( 5 * 1 0 8 ) ( a 2 1 . 6 ) 2

a 2 = 2

 Concentration of NH3 added =   a 2 = 2 M

 Volume of solution = 2L

 Moles of NH3 added = 2 * 2 mol = 4 mol.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

MCl3.2L => octahedral complex

M C l 3 . 2 L A g N O 3 ( e x c e s s ) 1 m o l e o f A g C l

It means one Cl- ion present in ionization sphere.

[ M C l 2 L 2 ] C l

For octahedral complex co-ordination numbers is 6

L is bidentate ligand i.e. its denticity is 2.

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