Coordination Compounds
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New answer posted
a month agoContributor-Level 10
Number of GI in [Co (NH? )? (NO? )? ] is 2 i.e, X
Number of GI in [Cr (C? O? )? ]³? is 0 i.e. Y
[X + Y] = 2
New answer posted
a month agoContributor-Level 9
(CH?)?N?HCl produces H? which reacts with NaHCO? and CO? gas evolved, because HCl is stronger acid than H?CO?
New answer posted
a month agoContributor-Level 10
[MnCl? ]³?
Mn (25) → [Ar] 4s²3d?
Cl? → weak ligand
Mn³? → 3d? i.e. t? g³, eg¹
Hybridization → sp³d² and paramagnetic
New answer posted
a month agoContributor-Level 10
(A) [PtCl? (NH? )? ], Number of GI = 2
(B) [Ni (CO)? ], Number of G.I = 0 as it is tetrahedral.
(C) [Ru (H? O)? Cl? ] Number of G.I = 2 (Facial and Meridional)
(D) [CoCl? (NH? )? ]? Number of G.I = 2 (Cis and trans)
New answer posted
2 months agoContributor-Level 10
In strong field of octahedral complex of Fe2+, the electronic configuration is,
Number of unpaired electrons are zero in the presence of strong field ligand.
Hence, spin only magnetic moment =
New answer posted
2 months agoContributor-Level 10
x + 4 * 0 – 2 * 1 = +1
x = +3
Fe+3 = 4s0 3d5
In presence of strong ligand, i.e, CO.
Spin only magnetic moment
New answer posted
2 months agoContributor-Level 10
t = 00.8 M
0 5 * 10-8 M 0.8M
Concentration of NH3 added =
Volume of solution = 2L
Moles of NH3 added = 2 * 2 mol = 4 mol.
New answer posted
2 months agoContributor-Level 10
MCl3.2L => octahedral complex
It means one Cl- ion present in ionization sphere.
For octahedral complex co-ordination numbers is 6
is bidentate ligand i.e. its denticity is 2.
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