Coordination Compounds

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New answer posted•a year ago

Coordination Compounds Class 12th

The type of hybridisation and magnetic property of the complex [MnCl?]³?, respectively, are:

8 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

[MnCl? ]³?
Mn (25) → [Ar] 4s²3d?
Cl? → weak ligand
Mn³? → 3d? i.e. t? g³, eg¹
Hybridization → sp³d² and paramagnetic

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New answer posted•a year ago

Coordination Compounds Class 12th

The number of geometrical isomers found in the metal complexes [PtCl?(NH?)?], [Ni(CO)?], [Ru(H?O)?Cl?] and [CoCl?(NH?)?]? respectively are

4 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

(A) [PtCl? (NH? )? ], Number of GI = 2

(B) [Ni (CO)? ], Number of G.I = 0 as it is tetrahedral.
(C) [Ru (H? O)? Cl? ] Number of G.I = 2 (Facial and Meridional)

(D) [CoCl? (NH? )? ]? Number of G.I = 2 (Cis and trans)

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New answer posted•a year ago

Coordination Compounds Class 12th

The number of stereoisomers possible for ${[C o {(o x)}_{2} (B r) (N H_{3})]}^{2 -}$  is…………

[ox = oxalate]

2 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Kindly consider the following figure

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New answer posted•a year ago

Coordination Compounds Class 12th

Match List – I and List – II.

Choose the correct answer from the options given below:

7 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Kindly consider the following figure

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New answer posted•a year ago

Coordination Compounds Class 12th

Spin only magnetic moment of an octahedral complex of Fe²⁺ in the presence of a strong field ligand in BM is:

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

In strong field of octahedral complex of Fe²⁺, the electronic configuration is,

$F e_{26}^{2 +} \to [A r] 3 d^{6} 4 s^{0}$

Number of unpaired electrons are zero in the presence of strong field ligand.

Hence, spin only magnetic moment = $\sqrt[]{n (n + 2)} = 0 B M (n = 0)$

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New answer posted•a year ago

Coordination Compounds Class 12th

Spin only magnetic moment in BM of ${[F e {(C O)}_{4} (C_{2} O_{4})]}^{+}$  is:

9 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

${[F e {(C O)}_{4} (C_{2} O_{4})]}^{+}$

x + 4 × 0 – 2 × 1 = +1

x = +3

Fe⁺³ = 4s⁰3d⁵

In presence of strong ligand, i.e, CO.

Spin only magnetic moment

$= \sqrt[]{n (n + 2)} B . M = \sqrt[]{1 (1 + 2)} B . M$

$\sqrt[]{3} B . M . = 1.73 B . M$

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New answer posted•a year ago

Coordination Compounds Class 12th

The number of miles of NH₃, that must be added to 2L of 0.80 M AgNO₃ in order to reduce the concentration of Ag⁺ions to 5.0 × 10^-8 M (K_formation for [Ag(NH₃)₂]⁺ = 1.0 × 10⁸) is_________.

(Nearest integer)

[Assume no volume change on adding NH₃]

74 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$A g^{+} (a q) + 2 N H_{3} (a q) ? A g {(N H_{3})}_{2}^{+} (a q)$

t = 00.8 M $(\frac{a}{2}) M$

0 $= \infty$ 5 × 10^-8 M $(\frac{a}{2} - 1.6) M$ 0.8M

$k_{f} = \frac{[A g {(N H_{3})}_{2}^{+}]}{[A g^{+}] {[N H_{3}]}^{2}}$

$1 0^{8} = \frac{0.8}{(5 \times 1 0^{- 8}) {(\frac{a}{2} - 1.6)}^{2}}$

$\frac{a}{2} = 2$

Concentration of NH₃ added = $\frac{a}{2} = 2 M$

Volume of solution = 2L

Moles of NH₃ added = 2 × 2 mol = 4 mol.

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New answer posted•a year ago

Coordination Compounds Class 12th

1 mol of an octahedral metal complex with formula MCl₃ $\cdot$ 2L on reaction with excess of AgNO₃ gives 1 mol of AgCl. The denticity of Ligand L is________(integer answer)

2 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

MCl₃.2L => octahedral complex

$M C l_{3} . 2 L \overset{A g N O_{3} (e x c e s s)}{\to} 1 m o l e o f A g C l$

It means one Cl^- ion present in ionization sphere.

$∴ [M C l_{2} L_{2}] C l$

For octahedral complex co-ordination numbers is 6

$∴ L$ is bidentate ligand i.e. its denticity is 2.

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New answer posted•a year ago

Coordination Compounds Class 12th

Which one of the following complexes is violet in colour?

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

${[F e {(C N)}_{5} N O S]}^{4 -}$ ${_{}}^{}$ Violet colour

${_{}}^{}$ ${[F e {(S C N)}_{6}]}^{4 -}$ Blood red colour

$F e_{4} {[F e {(C N)}_{6}]}_{3} H_{2} O \to$ Prussian blue colour

${[F e {(C N)}_{6}]}^{4 -} \to$ Yellow colour

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New answer posted•a year ago

Coordination Compounds Class 12th

Amongst FeCl₃.3H₂O, K₃ $[F e {(C N)}_{6}] a n d [C o {(N H_{3})}_{6}] C l_{3},$  the spin- only magnetic moment value of the inner-orbital complex that absorbs light at shortest wavelength is ________ B.M [nearest integer]

4 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

FeCl₃. 3H₂O i.e. [Fe(H₂O)₃], K₃[Fe(CN]₆ and [Co(NH₃)₆]Cl₃; the last two complex are inner-orbital complex due to presence of strong ligand.

$∴ Δ_{0} o f K_{3} [F e {(C N)}_{6}] > Δ_{0} o f [C o {(N H_{3})}_{6}] C l_{3}$

Because CN^- is strong ligand

$∴ Δ_{0} \propto \frac{1}{λ}$

More $Δ_{0}$ smaller value of absor

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