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Coordination Compounds

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2 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Consider the following reaction.

$2 H S O_{4}^{-} (a q) \to_{(2) H y d r o l y s i s}^{(1) E l e c t r o l y s i s} 2 H S O_{4}^{-} + 2 H^{+} + A$

The dihedral angle in product A in its solid phase at 110 K is

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Payal Gupta

Contributor-Level 10

During the electrolysis of dilute H₂SO₄

$2 H_{2} S O_{4} \overset{(1) e l e c t r o l y s i s}{\to} 2 H S O_{4}^{-} + 2 H^{+}$

$H_{2} S_{2} O_{8} + 2 H_{2} O \overset{h y d r o l y s i s}{\to} 2 H_{2} S O_{4} + \underset{(A)}{H_{2} O_{2}}$

$2 H^{+} + 2 e \to H_{2} ↑$

In the solid form of $H_{2} O_{2}$ dihedral angle is equal to 90.2°.

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2 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Match List I with List II

Choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

The number of isomers possible for $[P t (e n) {({N O}_{2})}_{2}]$ is:

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2 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

The pair in which both the species have the same magnetic moment (spin only) is:

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alok kumar singh

Contributor-Level 10

${C r}^{2 +}$ and ${F e}^{2 +}$ both have 4 unpaired electrons.

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2 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Number of complexes which will exhibit synergic bonding amongst $[C r {(C O)}_{6}], [M n {(C O)}_{5}]$ and $[M n_{2} {(C O)}_{10}]$ is_______________.

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Payal Gupta

Contributor-Level 10

All metal carbonyls have synergic bonds.

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Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Given below are two statements:

Statement I : ${[N i {(C N)}_{4}]}^{2 -}$ is square planar and diamagnetic complex, with dsp² hybridizatin for Ni but $[N i {(C O)}_{4}]$ is tetrahedral, paramagnetic and with sp³ hybridization for Ni.

Statement II : ${[N i C l_{4}]}^{2 -} a n d [N i {(C O)}_{4}]$ both have same d-electron configuration have same geometry and are paramagnetic.

In light the above statements, choose the correct answer from the options given below

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Payal Gupta

Contributor-Level 10

${[N i {(C N)}_{4}]}^{2 -}$

CN is strong field ligand

$N i^{2 +} = 4 s^{0} 3 d^{8}$

Here; ${[N i {(C N)}_{4}]}^{2 -}$ is square planar and diamagnetic.

$[N i {(C O)}_{4}]$

Ni = 4s²3d⁸Co is strong field ligand.

Here ; $[N i {(C O)}_{4}]$ is tetrahedral and diamagnetic

${[N i {(C N)}_{4}]}^{2 -}$ has 3d⁸ configuration while $[N i {(C O)}_{4}]$ has 3d¹⁰ configuration.

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2 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

${[F e {(C N)}_{6}]}^{3 -}$ should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is (-) _________ $Δ_{0} .$ (Nearest integer)

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Vishal Baghel

Contributor-Level 10

In complex ${[F e {(C N)}_{6}]}^{- - -}$

CN is the strong field ligand

$F e^{3 +} \to 3 d^{5} [t_{2 g}^{5} e_{g}^{0}]$

CFSE value = 5 * $(- 0.4 Δ_{0}) = - 2.0 Δ_{0}$

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3 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

The Crystal Field Stabilization Energy (CFSE) of $[{C o F}_{3} {(H_{2} O)}_{3}] (Δ_{0} < P)$ is :

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alok kumar singh

Contributor-Level 10

Sol. (a) In extraction of iron lime stone is added on a flux

$\begin{array}{r} {C a C O}_{3} ? C a O + {C O}_{2} \\ {C O}_{2} + {S i O}_{2} ? {C a S i O}_{3} \end{array}$

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Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Arrange the following coordination compounds in the increasing order of magnetic moments (Atomic numbers: Mn = 25; Fe = 26)

(A) ${[F e F_{6}]}^{3 -}$ (B) ${[F e {(C N)}_{6}]}^{3 -}$ (C) ${[M n C l_{6}]}^{3 -}$ (high spin) (D) ${[M n {(C N)}_{6}]}^{3 -}$

Choose the correct answer from the options given below

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Payal Gupta

Contributor-Level 10

A. ${[F e F_{6}]}^{3 -}$

Fe³⁺ - 3d⁵4s⁰

F^- is weak field ligand, so no pairing of electrons :

Number of unpaired electrons, n = 5

B. ${[F e {(C N)}_{6}]}^{3 -}$

$F e^{3 +} - 3 d^{5} 4 s^{0}$

CN^- is strong field ligand, so pairing of electrons takes place.

Number of unpaired electrons, n = 1

C. ${[M n C l_{6}]}^{3 -}$

...more

A. ${[F e F_{6}]}^{3 -}$

Fe³⁺ - 3d⁵4s⁰

F^- is weak field ligand, so no pairing of electrons :

Number of unpaired electrons, n = 5

B. ${[F e {(C N)}_{6}]}^{3 -}$

$F e^{3 +} - 3 d^{5} 4 s^{0}$

CN^- is strong field ligand, so pairing of electrons takes place.

Number of unpaired electrons, n = 1

C. ${[M n C l_{6}]}^{3 -}$

$M n^{3 +} - 3 d^{3} 4 s^{0}$

Number of unpaired electrons, n = 3

D. ${[M n {(C N)}_{6}]}^{3 -}$

$M n^{3 +} - 3 d^{3} 4 s^{0}$

Number of unpaired electrons, n = 3

Higher the number of unpaired electrons. Then higher be the magnetic moment as;

Magnetic moment, $μ = \sqrt[]{n (n + 2)} B . M$

Hence, order of magnetic moment is ;

B < D = C < A

less

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3 months ago

Coordination Compounds Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Assertion: [Fe(CN)₆]^3- ion shows magnetic moment corresponding to two unpaired electrons.

Reason: Because it has d²sp³ type hybridisation.

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Vishal Baghel

Contributor-Level 10

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: Correct option: D

[Fe (CN)₆]^3- ion shows magnetic moment corresponding to one unpaired electron. (CN) is a ligand with a strong field that couples electrons, resulting in hybridisation. d²sp³ and it has one unpaired electron, it has the magnetic moment of one paired electron.

μ= $\sqrt[]{n (n + 2}$ = 1 (1 + 2)

= 3 = 1.73BM

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