Data Interpretation

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P
Payal Gupta

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Directions for questions: Answer the questions on the basis of the information given below. Given below is a network of oil pipelines and nine hubs– A through I. The requirement of oil at the hubs is exactly met by the flow in the pipelines. The flow in some of the pipelines and the requirement at some of the hubs is also mentioned. A is the only hub which is a source hub, i.e. the hub A does not have any requirement of its own but it supplies the requirement of all the other hubs.

It is also known that

I. The maximum capacity of any pipeline is 1000.

II. The requirement at any hub except A and I is equal to the flow in exactly on

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P
Payal Gupta

Contributor-Level 10

As not two pipelines connecting same place are carrying same amount, and at least one of the pipelines should carry same as that of the place, either H-I or G-H must carry 300. If G-H carries 300, then H-I must carry 200, which is not possible.

H-I must carry 300 and G-H must carry 400. D-G should carry 400 more than the requirement at G.

G's requirement must equal that of G-H

Requirement at G = 400 D-G = 800

The flow in El must be equal to the requirement at E, and each of them must be equal to 100. Therefore the requirement at I = 100 + 300 = 400.

Considering F, the flow in FB must be equal to the requirement at F, i.e., 100, and the flo

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