DILR Preparation Tips for MBA
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New answer posted
2 months agoContributor-Level 10
In the two years, 2018 & 2019, the required percentage is more than 25 % but it happened in 2011 for the first time.
New answer posted
2 months agoContributor-Level 10
Profitable can be either A or D. Then aggressive and honest has to be B and C. Hence, truthful is A or D. And for both A and D the lowest revenue is from S1
New answer posted
2 months agoContributor-Level 10
B is honest according to Statement (I) Atmost only one statement can be true as both give Aggressive and Honest as firm B.Firm B cannot have two names.
New answer posted
2 months agoContributor-Level 10
According to statement (I) aggressive is (B). Then F1. has to be C (as given in neutral statement).
Then statement (II) is also true, F1's the lowest revenue is from Bihar.
New answer posted
2 months agoContributor-Level 10
As F3. has the highest market share hence Truthful Ltd. can be A or C. From neutral statement either B and C are aggressive and honest or A and D are aggressive and honest. According to statement (I), B is profitable, then A and D are aggressive and honest. Then honest total revenue cannot be more than that of profitable, hence statement (II) is false.
New answer posted
2 months agoContributor-Level 10
| Day 1 | Day 2 | Day 3 | Day 4 | Day 5 |
Start Price | 100 | 90 | 80 | 90 | 100 |
End Price | 90 | 80 | 90 | 100 | 110 |
Assume initial number of share with T1 and T2 is X. In the above table T1 by 10 share each on day 1, day 2 and sold 10 shares and day 3, day 4 and day 5.
Total share with T1 is X – 10.
In the above T2 buy share only on day 2.
Total shares with T2 is X + 10.
T2 had 20 shares more than T1.
Therefore at the end of day 3 the price of share is Rs. 90
New answer posted
2 months agoContributor-Level 10
| Day 1 | Day 2 | Day 3 | Day 4 | Day 5 |
Start Price | 100 | 110 | 120 | 130 | 120 |
End Price | 110 | 120 | 130 | 120 | 110 |
Let initial amount with T1 and Michal is .
T1 sold shares on Day 1, Day 2, Day 3, whereas buys shares on Day 4 and Day 5.
Total money with T1 is = Y + 110 * 10 + 120 * 10 + 130 * 10 – 120 * 10 – 110 * 10 = Y + 1300
Total money with T2 = Y + 1200
Total money with T2 = Y + 120 * 10 + 130 * 10 + 120 * 10 = Y + 3700
Total money with T2 & T1 = 2Y + 5000.
Therefore maximum possible increase is 5000.
New answer posted
2 months agoContributor-Level 10
| Day 1 | Day 2 | Day 3 | Day 4 | Day 5 |
Start Price | 100 | 90 | 100 | 110 | 100 |
End Price | 90 | 100 | 110 | 100 | 100 |
Let initial amount with T1 and T2 is Y.
Total Money with T1 = Y – 900 + 1000 + 1100 + 1200 – 1100 = Y + 1300
Total money with T2 = Y
Therefore, T1 ended up with Rs. 1300 more cash than T2.
Therefore at the end of day 4 the price of share is Rs.100.
New answer posted
2 months agoContributor-Level 10
| Day 1 | Day 2 | Day 3 | Day 4 | Day 5 |
Start Price | 100 | 90 | 100 | 110 | 120 |
End Price | 90 | 80 | 110 | 120 | 110 |
Let initial amount with T1 and T2 is Y.
Total money with T1 = Y – 900 + 1000 + 1100 + 1200 – 1100 = Y + 1300
Total money with T2 = Y + 1200
Therefore difference between T1 and T2 is Rs. 100 and Number of shares with T2 and T1 is same.
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