DILR Preparation Tips for MBA

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2 months ago

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Payal Gupta

Contributor-Level 10

R4 → D5 → DR2

The least cost to reach to AAB is for AE. And that is BD to AE is zero.

New answer posted

2 months ago

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Payal Gupta

Contributor-Level 10

If you look for large figures you would find them in both tables in D5.

 the largest cost = 1157.7 + 1035.3

= 2193.00

New answer posted

2 months ago

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P
Payal Gupta

Contributor-Level 10

Number of refineries = 6

Number of depots = 7

Number of districts = 9

Therefore, number of possible ways to send petrol from any refinery to any district is 6 * 7 * 9 = 378.

New question posted

2 months ago

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New answer posted

2 months ago

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P
Payal Gupta

Contributor-Level 10

Total number of excellent students = 120

Number of female excellent students = 70

Required fraction

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2 months ago

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Payal Gupta

Contributor-Level 10

Number of female good students = 8

Number of males average students = 48

Required ratio = 8 : 48 = 1 : 6

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Payal Gupta

Contributor-Level 10

From the above table, it is clear that number of female good students = 8

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2 months ago

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Payal Gupta

Contributor-Level 10

From (II), 40% of total number of students = 96

Total number of students = (96/40)*100=240

 

Number of boys = 240 – 96 = 144

From (I), number of average male students =144/3=48

 

From (III), number of excellent students = 240/2= 120

 

Number of excellent female = 120 – 50 = 70

From these calculations, we get the following table.

 

 

Performance

Total

Average

Good

Excellent

Male

48

46

50

144

Female

18

8

70

96

Total

66

54

120

240

From the above table, it is clear that number of male good students = 46

New answer posted

2 months ago

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P
Payal Gupta

Contributor-Level 10

The answer can be obtained directly by increasing the answer in question 11 by 50%, as all the Children increase the cost by 50% and hence the total cost will increase by 50% only.

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