Dual Nature of Radiation and Matter

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New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

λ = h p o r λ = h m v

λ p = λ α [ G i v e n ]

h m p V p = h m α v α v p v α = m α m p

v p v α = 4 m m = 4 1 0r 4: 1

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

[h] = ML2T-1

[E] = ML2T-2

[V] = ML2T-2C-1

[P] = MLT-1

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

K = qV

p = 2 m k = 2 m q V

λ = h p = h 2 m q V

λ p λ α = m α m p . q α q p = 4 * 2 = 2 * 1 . 4 = 2 . 8

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

Energy corresponding to a particle is mc2

hcλ=mc2hcλ= (x3h)c2x=3λc=310*1010*3*108 = 1101=10

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

Using de-Broglie equation for wave nature of particle :

λ=hcmvλα1m

λeλP=1me1mP=mPme=1836

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

Stopping potential defined in terms of wavelength as :

eV=hcλ? 0.710eV=hc491? 1.43eV=hcλ?

Using above two equation we can calculate :

λ=382nm

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

(A) If c  is the velocity of light

so,   E = h ν   (Energy of photon)

(B) Velocity of photon is equal to velocity of light i.e. c.

(C)  λ = h p

p = h λ

p = h v c

(D) In photon-electron collision both total energy and total momentum are conserved.

New answer posted

3 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

In the case for maximum elongation,

Stress = Elastic limit

δ m a x = σ elastic  * L  Young's modulus  = 8 * 1 0 8 * 1 2 * 1 0 1 1 = 4 * 1 0 3

=4 mm

i.e. maximum elongation is 4 mm

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

E=IA

=100*1*104

=102W

E=nhcλ

102=n? *6.64*1034*3*108900*109

n? =102*9*1076.64*1034*3*108

n? =4.5*1016

New answer posted

3 months ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

de-Broglie wavelength λ = h P = h m v = h 2 m E where E = 1 2 m v 2

Squaring both sides,

λ 2 = h 2 4 m 2 E

1 λ 2 = (  constant  ) E

Graph passes through origin with constant slope.

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