Dual Nature of Radiation and Matter

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a month ago

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V
Vishal Baghel

Contributor-Level 10

In case 1, E? = 2eV; φ? ? = E? - KE? = 1eV
In case 2, E? = 12400/1550 = 8eV; max.KE = 8eV - 1eV = 7eV

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

p = h λ  

So, two photons having equal linear momenta have equal wavelength. As wavelength decreases, momentum and energy of photon increases.

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

λ? = h/√2mE? = λ? = h/√2mE?
=> E? = (4/9)E? = 4eV
E? = E? - eV? => V? = 5V

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

p = nhc/λ ⇒ n = pλ/hc
n = (3.3 * 10? ³ * 600 * 10? ) / (6.6 * 10? ³? * 3 * 10? ) = 10¹?

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

hc/λ = K? + φ [given φ is negligible]
So, hc/λ = K?
λ? = h/√ (2mK? ²) ⇒ K? = h²/ (2mλ? ²)
(hc)/λ = h²/ (2mλ? ²) ⇒ λ = (2mc/h)λ? ²

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Incident energy = 2.20 e V

If ? < 2.20 e V  electron will emit.

? > 2.20 e V No electron emission

Only caesium will emit electron

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

λ = h p

Graph will be hyperbolic

 

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Let height of bridge = h

Displacement of ball, S = - h

S = u t + 1 2 a t 2 - h = 4 * 4 + 1 2 ( - 10 ) ( 4 ) 2 h = 64 m

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

(bonus)

Using the equation

e V = h v - ?

or 

e V 2 = h v 2 - h v T h

e V s = h u - h u T h

Data Incorrect

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

R = (2μ sinθ) / (1.22λ) . (1)

According to de-Broglie's hypothesis, we can write
λ = h / (mv) . (2)

With the help of equations (1) and (2), we can write
R = (2μmv sinθ) / (1.22h) ⇒ R? /R? = m? /m? = 1837 ⇒ R? = 1837R?

  • Concept involved: Resolving Power of Microscope
  • Topic: Optics
  • Difficulty level: Moderate
  • Point of Error: Formula

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