Engineering Entrance Exam
Get insights from 45.7k questions on Engineering Entrance Exam, answered by students, alumni, and experts. You may also ask and answer any question you like about Engineering Entrance Exam
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New question posted
6 months agoNew question posted
6 months agoNew answer posted
6 months agoContributor-Level 9
Yea. You can easily get the ECE with your rank in the upcoming round. As a rank with 6056 is already very close and the Amrita CBE have always a slight range distance for ECE every year.
New answer posted
6 months agoContributor-Level 7
The admission to BTech and BTech courses has been started through JEE Main. Additionally, the institute has released the Round 1 seat allotment result wherein B.Tech. in Computer Science and Engineering (Internet of Things, Cyber Security including Block Chain Technology) closing rank stood at 47166 for the General AI quota.
Moreover, the JEE Advanced Counselling 2024 was conducted in six rounds for admission to the BTech and other UG courses. The JEE Advanced Counselling Process includes steps like registration, choice filling, and paying the counselling fee. Candidates will then be called for document verification, where their el
New answer posted
6 months agoContributor-Level 7
Recently, NIELIT Patna cutoff 2025 for the Round 1 seat allotment has been released by the institute for the admission to BTech and BTech Integrated courses. As per the JEE Main 2025 cut off data, the B.Tech. in Computer Science and Engineering rank stood at 50162 for the General AI category candidates. Similarly, for the OBC AI quota, the rank stood at 18790.
Candidates seeking admission to NIELIT Patna via JEE Main 2025 must need to sit for the counselling rounds to get selected for the admission to any BTech or BTech Integrated course of thier choice. Although, he/she must have to confirm their seat if someone is willing to opt
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
Explanation-number of photon emitted per second n=
(ii) E=hc = this enegy is greater than 2 so emission is possible
(iii) work function = =
= =
(iv) N=
= =2
(v) as the time of emission is 11.04s so photoelectric is not spontaneous.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 680k Reviews
- 1800k Answers
