Gravitation

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New answer posted•a year ago

Gravitation Physics Gravitation

8.3 Suppose there existed a planet that went around the Sun twice as fast as the earth. What would be its orbital size as compared to that of the earth?

20 Views|Posted a year ago

Asked by Vishal Baghel

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Vishal Baghel | Contributor-Level 10

a year ago

Time taken by the Earth to complete one revolution around the Sun, $T_{e}$ = 1 year

Orbital radius of the Earth in its orbit, $R_{e}$ = 1 AU

Time taken by the planet to complete one revolution around the Sun, $T_{p}$ = $\frac{1}{2} T_{e}$ = $\frac{1}{2}$ year

Orbital radius of the planet = $R_{p}$

From Ke

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New answer posted•a year ago

Gravitation Physics Gravitation

8.2 Choose the correct alternative:

(a) Acceleration due to gravity increases/decreases with increasing altitude

(b) Acceleration due to gravity increases/decreases with increasing depth (assume the earth to be a sphere of uniform density)

(c) Acceleration due to gravity is independent of mass of the earth/mass of the body

(d) The formula –G Mm(1/r₂ – 1/r₁) is more/less accurate than the formula mg(r₂ – r₁) for the difference of potential energy between two points r₂ and r₁ distance away from the centre of the earth

7 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

(a) Decreases - Acceleration due to gravity at depth h is given by $g_{h}$ = (1 – $\frac{2 h}{R_{e}}$ )g, where $R_{e} = R a d i u s o f t h e e a r t h,$ g = acceleration due to gravity on the surface of the Earth. From this equation, it is clear that acceleration due to gravity decreases with increase in height

(b) Decreases – Acceler

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8.3 Suppose there existed a planet that went around the Sun twice as fast as the earth. What would be its orbital size as compared to that of the earth?