JEE Main
Get insights from 28k questions on JEE Main, answered by students, alumni, and experts. You may also ask and answer any question you like about JEE Main
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
10 months agoBeginner-Level 5
Yes, you may be eligible for admission to the CSE/ECE branch at SASTRA Thanjavur/Kumbakonam campus with 969 marks in +2 grade and 62% in JEE Mains if you meet the following requirements:
You passed the +2 exam with a minimum aggregate of 60% in Physics, Mathematics, and Chemistry/Bio-Technology/Computer Science/Biology
You took the JEE Main exam
You are not more than 20 years of age as of August 1, 2025
SASTRA calculates its own ranks for admission based on +2 marks and JEE (Main) scores. Applicants are advised to submit their JEE scores even if they are not qualified for the Advanced or they don't have the cut-off prescribed by MHRD
New answer posted
10 months agoContributor-Level 10
With a 30685 EWS rank in JEE Mains, you can in all likelihood anticipate to get admission into newer NITs or less famous branches in installed NITs, potentially consisting of NITs like NIT Agartala, NIT Manipur, NIT Silchar, NIT Patna, or NIT Delhi for certain non-middle branches depending at the particular software and availability of seats.
New answer posted
10 months agoContributor-Level 10
Inconsistent names across documents, like your 10th and 12th marksheets, can sometimes cause confusion during the admission process. However, it generally won't directly affect your JEE 2025 admission, as long as you have supporting documents to clarify the discrepancy.
To avoid any issues, it's advisable to:
- Provide an affidavit: You can submit an affidavit or a gazette notification stating that both names refer to the same person.
- Check with authorities: Before your JEE application, contact the exam authority or the college for guidance and to ensure all your documents are in order.
It's always better to clarify these discrepancies well
New answer posted
10 months agoContributor-Level 10
Admission to the B.Tech Mathematics and Computing program at IISc (Indian Institute of Science) through JEE Mains typically requires a high rank, as IISc is one of the premier institutes in India. While the exact cutoff varies each year based on factors like the number of applicants, difficulty level of the exam, and seat availability, a rank within the top 250-300 is generally considered competitive.
For JEE Mains 2025, it will be good to aim for a percentile above 99 to improve your chances of admission. IISc considers other entrance exams like JEE Advanced, KVPY, or NEET for admissions, so exploring multiple options may also be helpf
New answer posted
10 months agoContributor-Level 6
The required documents for JEE Mains are: Class 10 and lass 12 certificates.Aadhar card details.Scanned photograph and signature.Scanned copy of the category certificate (if applicable).Scanned copy of the PwD certificate (if applicable). Income certificate and EWS certificate for backward castes.These are the main documents required for registration in JEE Mains exam.
New answer posted
10 months agoContributor-Level 7
JEE Main ranks are required for admission to BTech courses at the Millennium Group of Institution. The ranks for admission in 2024 varied from 93293 to 849268 based on different rounds, the category to which the student belongs, and the specialisation of BTech in which the student is interested. You can find the detailed cutoff on: Millennium Group of Institution Cutoff 2024 (Out): Check MPPET Cutoff Ranks & Trends.
New answer posted
10 months agoContributor-Level 9
BTech is one of the most desired courses present in India. BTech being the most preferred course, has the highest level of competition. JEE Main is the commonly accepted entrance exam for admission to the BTech course. Similarly, IIEST Shibpur also accepts JEE Main scores for admission to the BTech course. Students must foresee the coming cut by looking at the past year's cut-off details so that preparation can be done accordingly.
New answer posted
10 months agoBeginner-Level 4
First of all, Congrats on getting 94.5% in JEE Mains
Your JEE Main Paper-2 percentile of 94.5% and NATA score of 134 are eligible for B.Arch admissions. However, your Class 12th score of 67.5% may not meet the typical eligibility criteria.
It's important to note that eligibility criteria can vary by institution and may change over time.
It's advisable to contact PVPCOA directly to confirm your eligibility based on your academic credentials and the current admission criteria.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 678k Reviews
- 1800k Answers