JEE Main

Yes, AAA College of Engineering and Technology offers scholarships to students with a JEE Main score. Students having valid JEE Main score of 50 and above with 60% aggregate in Class 12 are eligible for complete tuition fee waiver. The scholarship is offered only to 10 students.

Dear Kiranpreet,

The Joint Entrance Examination (JEE) Main for 2025 is being conducted in two sessions. Session 1 took place from January 22 to 30, 2025, and Session 2 is scheduled from April 1 to 8, 2025. The registration for Session 2 is currently open until February 25, 2025. You can apply through the official NTA website. The JEE Main serves as a gateway for admissions into undergraduate engineering programs across various esteemed institutions in India. For detailed information on eligibility, syllabus, and exam patterns, please refer to the official website.

I hope this information is helpful to you.

Inverse Trigonometric Functions is considered a moderated weightage topic, 1 question is expected from this chapter directly. However, ITF plays an important role to boost score through usgae of its properties in Calculus unit, which have a better weightage overall. Students must check the NCERT Solutions of Inverse Trigonometric functions to build a strong base. Students can check the NCERT ITF Solutions below;

Class 12 Math ITF Solutions

Cutoff Percentiles for JEE MAINS 2025:

General - 95+

Ews - 84+

OBC - 83+

SC - 65+

ST - 50+

It's advisable to regularly check the official JEE Mains website 

To access the 29 January 2025 shift 2 JEE Main paper, you can visit the official NTA website (jeemain.nta.nic.in) or trusted educational platforms like Shiksha and etc. where you can download the question paper PDF with solutions for both shifts of the exam; simply search for "JEE Main 2025 January 29 Shift 2 Question Paper" on their websites.