JEE Mains paper 2

Hi Ganesh,
You need to score minimum 25 percent in both the sections of NATA paper. As you have not answered the drawing section, that is why your rank has been decreased. If you are pass in the NATA then you can get admission in good architecture colleges like LPU, Amity University, SRM, MS Ramaiya Bangalore, D Y patil college, etc.

Hi,
You should go for NIT Durgapur, IIEST Shibpur, Sir J J College of Architecture, MS Ramaiah Bangalore and D Y Patil College. These are some good colleges. You are eligible to get admission in all the NITs, so try there first.

Hi,
You should go for MNNIT Jaipur, NIT Jamshedpur, NIT Durgapur, IIEST Shibpur, MS Ramaiah Bangalore and SRM with this rank in JEE Mains. You will easily get a seat in these B.Arch colleges.

Hello Sanjay,
Yes, you are eligible to take admission in NIT you have to participate in JoSAA counselling to get admission into any IIT or NIT. JoSAA counselling is about to start so keep an eye on the NDT website.

Hello Monish,
You can get NITs. Use the college predictor to predict your college.

Hi Anusree, The minimum 25% in NATA exam is required to get qualified in NATA itself. If you score 100+ marks in NATA then you can expect an NIT. Best of luck.

Hi,
You can easily get admission in good architecture colleges with this score. You should apply for LPU, Sir J College of Architecture, D Y Patil College, SRM, MIT School of Architecture Pune, MS Ramaiya Bangalore, TCE Madurai, etc. You can also apply for some NITs like NIT Patna, NIT Jalandhar, NIT Jamshedpur, NIT Durgapur, IIEST Shibpur, etc.

Hi,
Yes, you are eligible to apply for Sir J J College of Architecture with this score. However, you will get a seat only in the second or third round in this college.

Please go with this link. This is a college predictor. I hope this will help you-
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor
Thank you

Please go with this college predictor hope this will help you:
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor.