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New answer posted
2 years agoContributor-Level 6
CV Raman Global University's B.Tech programme selection process is based on merit lists created by the institute. The merit lists are based on the marks scored by candidates in the JEE Main 2023 exam.
The central counseling process for B.Tech admission is administered by the Odisha JEE. Shortlisted candidates are called for counseling by Odisha JEE (OJEE) for the final selection.
New answer posted
2 years agoContributor-Level 7
In order to succeed in JEE Main and Advanced, eleventh graders must have a reference book for each topic in addition to NCERT texts. You can begin studying maths with Cengage, chemistry with NCERT, and physics with HC Verma Part 1 in class 11.
The greatest books for practising JEE Main and Advanced past year questions (PYQ) are Arihant and Disha. You may also get the JEE previous year's questions in PDF format.
You can also download the PYQs of JEE Main on the official site of the JEE Main 2024.
New answer posted
2 years agoContributor-Level 7
A percentile score of 83 in JEE Mains 2023 is predicted to result in an EWS category rank of 26,000–27,900 and a CRL rank of 153,450–172,500, according to one source.
If a candidate is ranked 500th overall or 50th among EWS candidates, they generally rank 49th in the category.
In 2024, admission to NITs will require a percentile of 85–90 for OBC and EWS applicants, and 95–97 for general category candidates.
A list of students from the general EWS category who took the JEE paper is known as the EWS rank in JEE Mains. Those who took the JEE paper are included in the common rank list, or CRL rank.
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New answer posted
2 years agoNew answer posted
2 years agoContributor-Level 7
For the previous three years, the predicted range of the JEE Main R1 seat allotment result for the B.Tech in Computer Science and Engineering at IIIT Hyderabad has been between 367 and 839. BTech ECE R1 candidates for the General category All India Quota must fall between 871 and 2211.
Typically, applicants seeking admission to IIIT Hyderabad need to score between 98 and 99 percentile in the JEE Main exam.
New answer posted
2 years agoContributor-Level 7
Several NITs and IIITs, such as NIT Jalandhar, NIT Agartala, NIT Durgapur, NIT Goa, NIT Hamirpur, NIT Meghalaya, NIT Raipur, and NIT Puducherry, might consider applicants with an 86 percentile.
NIT Jalandhar and NIT Hamirpur may be able to provide chemical to those who score in the 86 percentile.
Top private universities including JIT NOIDA, THAPAR UNIVERSITY, SRM UNIVERSITY, GRAPHIC ERA, LPU, CHANDIGARH UNIVERSITY, UPES DEHRADUN, and JECRC JAIPUR are among those that might accept applicants with an 86 percentile.
A JEE Main score of 250 or above is regarded as excellent. The 85–95 percentile score range is thought
New answer posted
2 years agoContributor-Level 7
If you scored in the top 95 per cent of JEE Mains, you can enrol in CSE at IIIT Manipur or IIIT Agartala.
For NITs, general category students must have a percentile of 95–97 in JEE Mains, according to analysis from the preceding year. applicants who identify as OBC/EWS must score in the 85–90 range, while SC/ST applicants must score in the 65–70 range.
If you score in the top 95 per cent of JEE Mains, these colleges will offer CSE programmes in 2024.
- Sanskrit University Jagannath University in Mathura Jaipur
- Unison University IMS
- University of Parul
New answer posted
2 years agoContributor-Level 7
On March 7, NTA landed the second session of the JEE Mains form rectification 2024. The JEE Mains application form correction window is available at jeemain.nta.ac.in, according to the officials. To make changes to their JEE Main 2024 application form, candidates have to enter onto the candidate site during session 2. The JEE Main 2024 form correction window was opened by the National Testing Agency on March 6. From December 6 to 8, the JEE Main 2024 Session 1 application form correction opportunity was open.
The revision of the JEE Main 2024 application form was a paid service. The JEE form correction fee could be paid by students via
New answer posted
2 years agoContributor-Level 7
Either National Level Tests administered by different authorities or University-conducted Common Entrance Tests (CET) are used for admission to study programmes at Guru Gobind Singh Indraprastha University (GGSIPU).
For numerous programmes, the CET entrance exam has been withdrawn as of the 2019–20 academic year. National Level Examinations will take its place. The National Level Test application number, as supplied by the relevant national test conducting body, must be accurately entered by applicants in the online University Application form.
Note: Applicants for non-CET programmes, such as B.Tech programmes, must complete
New answer posted
2 years agoContributor-Level 7
Overall Percentile considering Moderate Paper is 97.78 - 98.84.
The provided JEE Main 2024 marks vs. rank should be noted by candidates as suggestive only. In addition to announcing the JEE results, the authority will also release the IIT JEE Main grades vs. rank 2024. Using the JEE marks vs. rank data, candidates will be able to forecast a likely range of ranks. Aspirants to the NTA JEE Main exam frequently want to know how many marks are needed for a particular rank or what rank they are assigned for a given number of marks. In response to a student inquiry, Shiksha has made available the anticipated JEE Main scores by rank.
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