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M
M Akash

Beginner-Level 4

You stand a good chance of being accepted into prestigious NITs. Candidates should aim for a JEE score of 250 in order to be admitted to NIT. A 90 percentile or higher can lead to admissions to prestigious NITs like NIT Delhi and NIT Calicut. Even lower ranks—70,000 and above—can get you into less well-known NITs, such the NITs in Sikkim and Meghalaya. 

 

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2 years ago

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New answer posted

2 years ago

0 Follower 8 Views

S
Subhrajeet Harichandan

Contributor-Level 9

The Qualifying cutoff marks for B.Ed in JEE to get shortlisted for Inmantec Institute is to get 350+ marks with 50% of the 12th grade.

B.Ed JEE Cut Off Marks 2024 determines if a candidate is eligible for admission to the 2-year B.Ed programme.

ST/SC candidates have a 5 % reservation for the B.Ed. JEE at Inmantec Institute.

Therefore, a candidate cannot join Inmantec Institutions without U.P. B.Ed. JEE for B.Ed.

New answer posted

2 years ago

0 Follower 12 Views

S
Sankhayan Sadhukhan

Contributor-Level 6

Biju Patnaik University of Technology (BPUT), Rourkela, Odisha offers various UG and PG courses in various disciplines such as architecture, engineering, management, pharmacy etc. B.Tech is one of the popular course here. They take admission through JEE Main or OJEE Main rank. Candidates should have passed their 12th exam from Science stream with physics, mathematics,   chemistry/ biotechnology language or any other subject with a decent marks from a recognised board.

BPUT JEE Main cutoff 2022 for general category is between 214106 - 1506891. So, with your rank in JEE Main with OBC category you can easily take admission in the core

...more

New answer posted

2 years ago

0 Follower 15 Views

H
Himanshi Tirkha

Contributor-Level 10

Hi Aryan,

The last rank to be allocated in JEE 2023 by JoSAA counselling was 42,135. The cut-off was for the Indian Institute of Information Technology Manipur to enrol in the Electronics and Communication Engineering course.

I hope it will help.

Thank You.

New answer posted

2 years ago

0 Follower 15 Views

H
Himanshi Tirkha

Contributor-Level 10

Hello Nandhu!

I have calculated the JEE Mains score basis on the percentile. The formula used is (100 - P)/100) * N + 1, where P is the percentile and N is the total number of students. 

After the calculation based on your percentile, 50 - 60 out of 300 can be the possible score.

I hope it will help. You can reach out to us for further queries.

Thank You.

New answer posted

2 years ago

0 Follower 9 Views

M
Moksha Bhandari

Beginner-Level 5

For BNMIT Bangalore admission to B.Tech course the score of COMEDK UGET and KCET is considered (including 10+2 with 45%)
5% seats - based on marks in qualifying examination and CET 
30% seats - based on COMED-K Test 
25% seats – based on PUC, CET and COMED-K Rank 
These are the eligibility criterias for taking admission in BNM Institut of Technology. For further information, you can visit the official site for addmision process and fees structure, or can directly contact them with provide official mail id or contact number.

 

New answer posted

2 years ago

0 Follower 10 Views

M
Moksha Bhandari

Beginner-Level 5

BNMIT Bangalore considers COMEDK UGET and KCET scores (including 10+2 with 45%) for admission in B.Tech courses.
5% seats - based on marks in the qualifying exams and CET. 
30% seats - based on the COMED-K test. 
25% seats - based on PUC, CET, and COMED-K rank. 
These are the eligibility criteria for admission in BNM Institute of Technology. For more information regarding the admission procedure and fee structure, visit the official website, or contact them directly using the provided official email address or phone number.

 

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