Laws of Motion

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

 

For equilibrium along the incline plane is given by,

F cos 60° = mg sin 60°

  F = 0 . 2 × 1 0 × 3 2 × 1 × 2              

  = 2 3 N = 1 2 N              

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New answer posted•a year ago
S
a year ago

f=mv2R            

⇒ m v 2 R = μ N
 

m v 2 R = μ m g

⇒ 3 0 = μ × 7 5 × 1 0                

  μ = 3 0 × 3 0 7 5 0 = 1 . 2              

              Now, R = 48 m (new Radius of curvature)

  &nb

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Assume both the block is moving with common acceleration ‘a’ then

a = F m + M . . . . . . . ( i )

N = mg

N = 2g

f = m a = m F m + M

For no slipping

⇒ 2 F 1 0 ≤ g

F ≤ 5 g

F ≤ 5 × 9 . 8 F ≤ 4 9 . 0 N

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

COME

k ⋅ E i + P ⋅ E i = k ⋅ E f + P ⋅ E f

⇒ 0 + m g ( h + h 2 ) = 0 + 1 2 k ( h 2 ) 2 ⇒ 3 h 2 m g = 1 2 k h 2 4

⇒ 3 m g h = k 4 h 2 ⇒ 1 2 m g h = k ⇒ k = 1 2 × 0 . 1 × 1 0 0 . 1               

k = 120Nm-1

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New answer posted•a year ago
New answer posted•a year ago