Laws of Motion
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One end of a massless spring of spring constant k and natural length <!-- [if gte mso 9]><xml>
</xml><![endif]--> is fixed while the other end is connected to a small object of mass m lying on a frictionless table. The spring remains horizontal on the table. If the object is made to rotate at an angular velocity <!-- [if gte mso 9]><xml>
</xml><![endif]--> about an axis passing through fixed end, then the elongation of the spring will be
One end of a massless spring of spring constant k and natural length <!-- [if gte mso 9]><xml>
5.40 A thin circular loop of radius R rotates about its vertical diameter with an angular frequency . Show that a small bead on the wire loop remains at its lowermost point for . What is the angle made by the radius vector joining the centre to the bead with the vertical downward direction for = ? Neglect friction.
5.40 A thin circular loop of radius R rotates about its vertical diameter with an angular frequency . Show that a small bead on the wire loop remains at its lowermost point for . What is the angle made by the radius vector joining the centre to the bead with the vertical downward direction for = ? Neglect friction.

Let be the angle made by the radius vector joining the bead and the centre of the wire with the downward direction. Let, N be the normal reaction.
mg = N …….(1)
mr = N ……(2)
m(R ) = N
Hence N = m(R)
Substituting the value on N
5.39 A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is 0.15. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed ?
5.39 A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum of radius 3 m rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is 0.15. What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed ?

Mass of the man, m = 70 kg
Radius of the drum, r = 3 m
Coefficient of friction between the wall and his clothing, = 0.15
Number of revs of hollow cylindrical drum = 200 rev/min = 200/60 rev/s = 3.33 rev/s
The centripetal force required is provided by the normal N of the wall on the man
N = m&
5.38 You may have seen in a circus a motorcyclist driving in vertical loops inside a death well’ (a hollow spherical chamber with holes, so the spectators can watch from outside).
Explain clearly why the motorcyclist does not drop down when he is at the uppermost point, with no support from below. What is the minimum speed required at the uppermost position to perform a vertical loop if the radius of the chamber is 25 m ?
5.38 You may have seen in a circus a motorcyclist driving in vertical loops inside a death well’ (a hollow spherical chamber with holes, so the spectators can watch from outside).
Explain clearly why the motorcyclist does not drop down when he is at the uppermost point, with no support from below. What is the minimum speed required at the uppermost position to perform a vertical loop if the radius of the chamber is 25 m ?
When the motorcyclist is at the uppermost point of the death well, the normal reaction R on the motorcyclist by the ceiling of the chamber acts downwards. His weight mg also acts downwards. The outward centrifugal force acting on the motorcyclist is balanced by two forces.
R + mg = m , whe
5.37 A disc revolves with a speed of rev/min, and has a radius of 15 cm. Two coins are placed at 4 cm and 14 cm away from the centre of the record. If the co-efficient of friction between the coins and the record is 0.15, which of the coins will revolve with the record ?
5.37 A disc revolves with a speed of rev/min, and has a radius of 15 cm. Two coins are placed at 4 cm and 14 cm away from the centre of the record. If the co-efficient of friction between the coins and the record is 0.15, which of the coins will revolve with the record ?
Speed of revolution of the disc, n = rev/min = 100/3 rpm = 100/ (3
Angular acceleration = 2 = 2 = 3.492 rad/s
The coins revolve with the disc. The centripetal force is provided by the frictional force …. (1)
As v = r , the above eq
5.36 The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Fig. 5.22. The coefficient of friction between the box and the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 m s-2. At what distance from the starting point does the box fall off the truck? (Ignore the size of the box).

5.36 The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Fig. 5.22. The coefficient of friction between the box and the surface below it is 0.15. On a straight road, the truck starts from rest and accelerates with 2 m s-2. At what distance from the starting point does the box fall off the truck? (Ignore the size of the box).

Force on the box, F = MA = 40 2 N = 80 N
Frictional force, Ff = = 0.15 60 N
Net force = F – Ff = 80 – 60 = 20 N
From the equation F = ma, we get the backward acceleration produced in the box
a = 20/40 = 0.5 m/s2
From the equation s = ut + , to travel s = 5 m by
5.35 A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 m s-2 for 20 s and then moves with uniform velocity.
Discuss the motion of the block as viewed by
(a) A stationary observer on the ground
(b) An observer moving with the trolley
5.35 A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with 0.5 m s-2 for 20 s and then moves with uniform velocity.
Discuss the motion of the block as viewed by
(a) A stationary observer on the ground
(b) An observer moving with the trolley
Mass of the block = 15 kg
Coefficient of static friction between the block and the trolley = 0.18
Acceleration of the trolley = 0.5 m/s2
(a) Force experienced by block, F = MA = 15 0.5 = 7.5 N. This fore acts in the direction of motion of the trolley
Force of friction, Ff =  
5.34 Two bodies A and B of masses 5 kg and 10 kg in contact with each other rest on a table against a rigid wall (Fig. 5.21). The coefficient of friction between the bodies and the table is
0.15. A force of 200 N is applied horizontally to A. What are
(a) The reaction of the partition
(b) The action-reaction forces between A and B ? What happens when the wall is removed?
Does the answer to (b) change, when the bodies are in motion?
Ignore the difference between μs and μk

5.34 Two bodies A and B of masses 5 kg and 10 kg in contact with each other rest on a table against a rigid wall (Fig. 5.21). The coefficient of friction between the bodies and the table is
0.15. A force of 200 N is applied horizontally to A. What are
(a) The reaction of the partition
(b) The action-reaction forces between A and B ? What happens when the wall is removed?
Does the answer to (b) change, when the bodies are in motion?
Ignore the difference between μs and μk

Mass of the body A, = 5 kg
Mass of the body B, = 10 kg
Applied force = 200 N
Coefficient of friction between the bodies and the table, μs = 0.15
(a) The frictional force is given by the relation
fs = ( + )g = 0.15 22.5 N. towards left
H
5.33 A monkey of mass 40 kg climbs on a rope (Fig. 5.20) which can stand a maximum tension of 600 N. In which of the following cases will the rope break: the monkey
(a) Climbs up with an acceleration of 6 m s-2
(b) Climbs down with an acceleration of 4 m s-2
(c) Climbs up with a uniform speed of 5 m s-1
(d) Falls down the rope nearly freely under gravity?
(Ignore the mass of the rope)

5.33 A monkey of mass 40 kg climbs on a rope (Fig. 5.20) which can stand a maximum tension of 600 N. In which of the following cases will the rope break: the monkey
(a) Climbs up with an acceleration of 6 m s-2
(b) Climbs down with an acceleration of 4 m s-2
(c) Climbs up with a uniform speed of 5 m s-1
(d) Falls down the rope nearly freely under gravity?
(Ignore the mass of the rope)

Mass of the monkey = 40 kg
Maximum tension of the rope Tmax = 600 N
(a) When the monkey climbs up with an acceleration of 6m / s2
Tension in the rope, T – mg = ma
T = m (g+a) = 40 (10+6)= 640 N
Since T > Tmax, the rope will break
(b) When the monkey climbs down with an acceleration of 4m/s2
Tension
5.32 A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in Fig. 5.19. What is the action on the floor by the man in the two cases ? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding ?

5.32 A block of mass 25 kg is raised by a 50 kg man in two different ways as shown in Fig. 5.19. What is the action on the floor by the man in the two cases ? If the floor yields to a normal force of 700 N, which mode should the man adopt to lift the block without the floor yielding ?

Mass of the block = 25 kg
Mass of the man = 50 kg
Acceleration due to gravity = 10 m/s2
Weight of the block = 250 N
Weight of the man = 500 N
In the 1st case, the man lifts the block directly, applying an upward force, same as the block = 250 N
Due to Newton's 3rd law of motion, the downward reaction of t
