Maths NCERT Exemplar Solutions Class 12th Chapter Eleven
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New question posted
2 months agoNew answer posted
2 months agoContributor-Level 10
Since lies on
Now, normal at is ,
which passes through
So,
Also,
(From (i) and (ii)
Thus,
New answer posted
2 months agoContributor-Level 10
gen term =
For constant term
36 – 3r – rk = 0
for r = 1, 2, 4
12Cr212-r>28
Possible values of k = 3, 1
New answer posted
2 months agoContributor-Level 10

Equation of OQ is x . 0 + y . 0 – (x + 0) – 2 (y + 0) = 0
⇒ x + 2y = 0 ……… (i)
Equation of PQ is
Solving (i) & (ii),
New answer posted
2 months agoContributor-Level 10
(a, 4a, 7). (3, 1, 2b)= 0
3a + 4a – 14b = 0 a – 2b = 0 ……. (i)
(a, 4a, 7) . (b, a, 2) = 0
ab – 4a2 + 14 = 0……… (ii)
(i) & (ii) =>2b2 – 16b2+ 14 = 0
Plane : x – y + z = 0
P (4, 5, 1)
4 + 5 + 1 = 10
New answer posted
2 months agoContributor-Level 10
A (1, 4, 3)
2x + my + nz = 4
7m + 3n = 16
m = 1, n = 3
Plane : 2x + y + 3z = 4
AM =
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