Mechanical Properties of Fluids

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7 months ago

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Vishal Baghel

Contributor-Level 10

Height of the spirit column,  h1 = 12.5 + 15 cm = 27.5 cm

Height of the water column,  h2 = 10 + 15 cm = 25 cm

Density of spirit,  ρ1 = 0.8 gm/ cm3

Density of water,  ρ2 = 1 gm/ cm3

Density of mercury,  ρ = 13.6 gm/ cm3

Let h be the difference between the levels of mercury in two limbs

Pressure exerted by mercury column of h height= h ρg = 13.6hg …. (i)

Difference between pressure exerted by water and spirit columns:

h2ρ2g-h1ρ1g=g25*1-27.5*0.8= 3g ……. (ii)

Equating equations (i) and (ii), we get

13.6hg = 3g

h = 3/13.6 = 0.221 cm

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Height of the spirit column, h1 = 12.5 cm = 0.125 m

Height of the water column, h2 = 10 cm = 0.1m

P0 = atmospheric pressure

ρ1 = density of spirit, ρ2 = density of water

Pressure at point B = P0 + h1ρ1g

Pressure at point D = P0 + h2ρ2g

But pressure at point B and D are same. Hence

P0 + h1ρ1g = P0 + h2ρ2g or h1ρ1 = h2ρ2

ρ1ρ2 = h2h1 = 1012.5 = 0.8

So the specific gravity of spirit is 0.8

New answer posted

7 months ago

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Vishal Baghel

Contributor-Level 10

The maximum mass of the car can be lifted, m = 3000 kg

Area of cross-section of the load carrying piston, A = 425 cm2 = 425 *10-4m2

Maximum force exerted by the load, F = mg = 3000 *9.8 N = 29400 N

Maximum pressure exerted, P = F/A = (29400 / 425 *10-4 ) Pa = 6.917 *105 Pa

New answer posted

7 months ago

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V
Vishal Baghel

Contributor-Level 10

The maximum allowable stress for the structure, P = 109 Pa

Depth of the ocean, d = 3 km = 3 *103 m

Density of water ρ = 103 kg/ m3

Acceleration due to gravity, g = 9.8 m/s

The pressure exerted because of sea water at the depth d = ρdg = 103* 3 *103*9.8 Pa

= 2.94 *107 Pa

The maximum allowable stress is more than the pressure, hence the structure is suitable.

New answer posted

7 months ago

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V
Vishal Baghel

Contributor-Level 10

Density of mercury,  ρ1 = 13.6 *103 kg/ m3

Density of wine,  ρ2 = 9.84 *102 kg/ m3

Height of the mercury column for atmospheric pressure,  h1 = 760 mm = 0.76 m

Height of the mercury column for atmospheric pressure = h2

From the relation, P = ρgh , since the pressure on both the system are equal

ρ1gh1 = ρ2gh2 , we get h2 = ρ1gh1ρ2g = 13.6*103*0.769.84*102 = 10.5 m

New answer posted

7 months ago

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V
Vishal Baghel

Contributor-Level 10

Mass of the girl, m = 50 kg

Diameter of the heel, d = 1.0 cm = 0.01 m, Radius of the heel, r = d/2 = 0.005m

Area of the heel,  πr2 = 7.85 *10-5 m2

Force exerted by heel on the floor, F = mg = 50 *9.8 N = 490 N

Pressure exerted by heel on the ground, p = F/A = 490/ (7.85 *10-5) N/ m2

= 6.24 *106 N/ m2

New answer posted

7 months ago

0 Follower 44 Views

V
Vishal Baghel

Contributor-Level 10

When air is blown under a paper, the velocity of air is more than the upper portion of the paper. As per Bernoulli's principle, atmospheric pressure reduces under the paper and makes it fall. To keep the paper horizontal, the air needs to be blown on the upper surface of the paper.

For a smaller opening, the flow of fluid is more than when it is bigger. When we try to close the tap with our fingers, water gushes through the small openings. Area and velocity are inversely proportional to each other.

Small opening of a syringe needle controls the velocity of the blood oozing out. At the constriction point of the syringe system, the flow ra

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New answer posted

7 months ago

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Vishal Baghel

Contributor-Level 10

The surface tension of a liquid is inversely proportional to temperature. Decreases

Most fluids offer resistance to their motion. It is like internal mechanical friction, known as viscosity. Gas viscosity increases with temperature, whereas liquid viscosity decreases with temperature. Because, intermolecular forces weaken with temperature increase, viscosity decreases.

With reference to the elastic modulus of rigidity for solids, the shearing force is proportional to the shear strain. With reference to elastic modulus of rigidity for fluids, the shearing force is proportional to the rate of shear strain.

For a steady-flowing fluid, an inc

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7 months ago

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Vishal Baghel

Contributor-Level 10

The angle between the tangent to the liquid surface at the point of contact and the surface inside the liquid is called the angle of contact ( θ) , as shown in the diagram

Sla = Interfacial tension between liquid-air interface

Ssl = Interfacial tension between solid -liquid interface

Ssa = Interfacial tension between solid-air interface

At the line of contact of contact, the surface forces between the three media must be in equilibrium. Hence

cos?θ = Ssa-SlaSla

The angle of contact θ is obtuse, if Ssa<Sla , as in the case of mercury on glass

This angle is acute if Ssl<Sla , as in the case of water on glass

Mercury molecules (which mak

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New answer posted

7 months ago

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V
Vishal Baghel

Contributor-Level 10

The pressure of a liquid is given by the following relation:

P = h ρ g, where P = Pressure, h = height of the liquid column,  ρ = is the density of the liquid and g= acceleration due to gravity

From the above relation, because of the h factor (height of the human body), the pressure is more at the feet and less at the brain

The said phenomenon is due to the ρ factor. Density of air is maximum at the sea level. At height, density decreases and pressure also decreases. At 6 km height, the density of air is nearly half of that of a t sea level

When pressure is applied on the liquid, the pressure is transmitted in all dir

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