Ncert Solutions Chemistry Class 11th
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6 months agoContributor-Level 10
(a) OH– ions can donate an electron pair and act as Lewis base.
(b) F– ions can donate an electron pair and actas Lewis base.
(c) H+ ions can accept an electron pair and act as Lewis acid.
(d) BCl3 can accept an electron pair since Boron atom is electron deficient. It is a Lewis acid.
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
An acid-base pair which differs by a proton only is known as conjugate acid-base pair. For example, HCl, and Cl represents conjugate acid base pair.
The conjugate acid/base for the species HNO2, CN–, HClO4F–, OH–, CO32-, and S2- are NO2–, HCN, ClO4–, HF, H2O, HCO3– and HS–.respectively.
New answer posted
6 months agoContributor-Level 10
Kc = [CH4] [H2O] / [CO] [H2]3
3.90 = [CH4]*0.02 / (0.30) (0.10)3
[CH4] = 3.90*0.30* (0.10)3 / 0.02
=5.85*102 M
Thus, the concentration of methane in the mixture is 5.85*102 M.
New answer posted
6 months agoContributor-Level 10
The equilibrium constant expression is
Kc = [O3]2 / [O2]3
2.0*1050 = [O3]2 / (1.6*102)3
[O3]2=2.0*1050* (1.6*102)3
=8.192*1056
Hence, the equilibrium concentration of ozone is
[O3]= 2.86*1028M
New answer posted
6 months agoContributor-Level 10
Following conclusions can be drawn from the values of Kc .
(a) Since the value of Kc is very small, this means that the molar concentration of the products is very small as compared to that of the reactants.
(b) Since the value of Kc is quite large, this means that the molar concentration of the products is very large as compared to that of the reactants.
(c) Since the value of Kc is 1.8, this means that both the products and reactants have appreciable concentration.
New answer posted
6 months agoContributor-Level 10
Let the partial pressures of CO and H2 be p.
CO (g) + H2?O(g) ? CO2?(g) + H2?(g)
Initial conc. 4 bar 4 bar 0 0
At equilibrium 4-p 4-p p
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