Ncert Solutions Chemistry Class 11th

Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th

Follow Ask Question
2k

Questions

0

Discussions

12

Active Users

29

Followers

New answer posted

6 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

5.6. The chemical equation for the reaction is
                                    2 Al + 2 NaOH + H2O? 2 NaAlO2 + 3H2 
i.e. 2 moles of Al give 3 moles of H2 gas.

Moles of aluminium = 270.15g = 5.56*10?3 moles

Moles of H2 produced= 23*5.56*10?3

           = 8.33*10?3 moles

           Volume of H2 = nRT / P

        &nbs

...more

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

5.5. Suppose molecular masses of A and B are MA and MB respectively. Then their number of moles will be

nA= 1/MA                                nB = 2/MB

Given: PA = 2 bar        and PA + PB = 3 bar

          => PB = 1bar

Since, PV = nRT

PA= nART and PBV= nBRT

Therefore, (PA / PB) = (nA / nB)= (MB / 2MA)

=> MB / MA = 2 x PA / PB = 2 x 2 /1 = 4

        => MB = 4 MA

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Answer: According to ideal gas equation
                        PV = nRT

Or                        P= nRT/V

Replacing n by m/M, we get

                            P M1 x 2 = 28 x 5 (Molecular mass of N2 = 28 g/mol)
or           

...more

New question posted

6 months ago

0 Follower 6 Views

New question posted

6 months ago

0 Follower 3 Views

New question posted

6 months ago

0 Follower 2 Views

New question posted

6 months ago

0 Follower 13 Views

New question posted

6 months ago

0 Follower 5 Views

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

5.1. Initial Pressure, P1 = 1 bar                           Final Pressure, P2 =?      

               Initial Volume, V1= 500 dm3                       Final Volume, V2=200 dm3
As the value of temperature constant (=30°C)
             &nbs

...more

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

KC= [SO3]2 / [SO2]2 [O2]

= (1.90)2 / (0.60)2 (0.82)

= 12.229 L mol-1

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.