Ncert Solutions Chemistry Class 12th

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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A
alok kumar singh

Contributor-Level 10

Carbon-chlorine bond cleavage is not possible in C H 3 = C H - C l

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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V
Vishal Baghel

Contributor-Level 10

Theory based.                                                                                                                               

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Theory based.                                                                                                                                              

New answer posted

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Concept based.

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A
alok kumar singh

Contributor-Level 10

6 N a O H + 3 C l 2 ? 5 N a C l + N a C l O 3 + 3 H 2 O

2 C a ( O H ) 2 + C l 2 ? C a ( O C l ) 2 + C a C l 2 + H 2 O

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R
Raj Pandey

Contributor-Level 9

Cr? O? ²? + 6Fe²? + 14H? → 2Cr³? + 6Fe³? + 7H? O
n-factor for Cr? O? ²? = 6, for Fe²? = 1
M.E Cr? O? ²? = M.E Fe²?
M? V? n? = M? V? n?
0.02 * 15 * 6 = M? * 10 * 1
M? = (0.02 * 15 * 6)/10 = 0.18 M = 18 * 10? ² M

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R
Raj Pandey

Contributor-Level 9

[Reactions showing reduction of various functional groups]
(1) Nitrile reduced to primary amine with H? /Ni.
(2) Nitrile and aldehyde reduced to primary amine and alcohol with LAH.
(3) Nitro group reduced to primary amine with Na/Hg, C? H? OH.
(4) Nitrile reduced to aldehyde with SnCl? /HCl.
Products of reaction 1, 2 and 3 are 1° amines, so react with Hinsberg's reagent to form sulphonamide. Product of (4) is an aldehyde, which does not react.

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