Ncert Solutions Chemistry Class 12th

Using, µ = √n (n+2) B.M, n = number of unpaired electrons.
? Ti? ³ = 4s? 3d¹, unpaired electron = 1
µ = 1.73 B.M
? V? ² = 4s? 3d³, unpaired electron = 3
µ = 3.87 B.M
? Sc? ³ = 4s? 3d? , unpaired electron = 0
µ = 0 B.M

Heating of cis-but-2-enedioic acid gives maleic anhydride as shown.
[Chemical reaction showing conversion of cis-but-2-enedioic acid to maleic anhydride upon heating]

PV = nRT

1 * V = $\frac{3.12}{32}*0.0821*300$

V = 2.4 litre

Vol of O₂ adsorbed per gm = 2.4 / 1.2 = 2 litre

$C{r}_2{O}_7^{2-}+2O{H}^{-}\to 2Cr{O}_4^{2-}+H_{2}O$

Dichromate ion converted to chromate ion in basic medium and oxidation number of Cr in $Cr{O}_4^{2-}$ is +6.

[Mn₂ (CO)₁₀]

Bridging ligand (CO) is (0)

O₃ generally exist in stratosphere and they acts as protector, because it protect us from harmful UV radiations but sometimes O₃ formed in troposphere and it acts as a pollutants.

O₃ in stratosphere : - Protector

O₃ in Troposphere : - Pollutant (photochemical smog)

Kernite $\left(N{a}_2{B}_4{O}_7.4H_{2}O\right)\to$ it is ore of boron

Cassiterite (SnO₂) → it is ore of tin

Calamine (ZnCO₃) → it is ore of zinc

Cryolite (Na₃AlF₆) → it is ore fluorine

Option (A) is false statement because estimation of nitrogen in an organic compound is done by Kjeldahl's method.