Ncert Solutions Maths class 11th

46. Slope of line 1 (passing) through (h. 3) and (4, 1) is

Kindly go through the solution

44. 

The slope of line x- 7y + 5 = 0 is

So, equation of line with slope m₂ and having x-intercept 3 is

y = m (x-d), d = x- intercept

⇒y = - 7 (x- 3)

⇒y = - 7x + 21

⇒ 7x + y- 21 = 0.

43. 

The slope of the line 3x - 4y + 2 = 0 is,

$m=-\frac{}{}$ \frac{3}{4}$$
$=\; -\frac{3}{-4}=\frac{3}{4}$

So, slope of line parallel to 3x - 4y + 2 = 0 is also m= $\frac{3}{4}$ .

Hence, this parallel line passes through ( -2, 3) we can write,

$m=\frac{y-y_0}{x-x_0}$

$\frac{3}{4}=\frac{y-3}{x-(-2)}=\frac{y-3}{x+2}$

3 (x + 2) = 4 (y - 3)

3x + 6 = 4y - 12

3x - 4y + 6 + 12 = 0.

3x - 4y + 18 = 0. Which is the required equation of line.

42. 

(i) Given, equation of lines are

15x + 8y- 34 = 0

15x + 8y + 31 = 0

So, c₁ = 34 and c₂ = 31, A = 15 and B = 8

19. Given, R= { (a, b): a, b $\in$ z and a – b is an integer}

We know that, the difference of two integers is also an integer.

R= { (a, b): a – b $\in$ z & a, b $\in$ z}

Domain of R=Z.

Range of R= Z.

18. Given, A={x, y, z}so, n(A)=3

B={1,2} so n(B)=2

? n(A * B)=n(A) *n(B)=3 * 2=6

Hence, no. of relation from A to B=Number of subsets of A * B

=2⁶

=64.

Kindly go through the solution

17. GivenR= { (x, x³) : x is a prime number less than 10}

R = { (x, x³) : x = 2,3,5,7}

= { (2,2³), (3,3³), (5,5³), (7,7³)}

= { (2,8), (3,27), (5,125), (7,343)}

40.

The given equation of the line is.

12 (x + 6) = 5 (y- 2)

⇒ 12x + 72 = 5y- 9

⇒ 12x- 5y + 72 + 9 = 0

⇒ 12x- 5y + 82 = 0

The perpendicular distance of point (-1, 1) from the line is given by