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New question posted
5 months agoNew answer posted
5 months agoContributor-Level 7
AIIMS Mangalagiri cutoff 2024 was released for admission to the MBBS course on the basis of NEET exam. The cutoff was released for different cateogories belonging to the All India quota. For the General AI category candidates, the cutoff rank was closed at 1930. Therefore, it is possible to get admission to the college with a rank of 1000, for the General AI category candidates.
New question posted
5 months agoNew answer posted
5 months agoContributor-Level 6
No. There is no government college which offers MBBS course in 300 marks. You can do MBBS private or go abroad for completing MBBS in these marks.
New answer posted
5 months agoContributor-Level 7
AIIMS Jodhpur MBBS cutoff 2024 has been released for the last round. The institute accepts NEET scores for admission to the MBBS course. The cutoff for the General AI category candidates was closed at 374. For the OBC AI category candidates, the last round closing rank was 695. For the SC AI and ST AI category candidates were 4912 and 10281, respectively.
Check this page for more information on AIIMS Jodhpur cutoff.
New answer posted
5 months agoContributor-Level 6
AIIMS Jodhpur NEET cutoff 2024 has been concluded for MBBS admission. The cutoff was released for different categories belonging to the All India quota. For the General AI category candidates, the last round closing rank was 374. Therefore, it is possible to get admission at 350 among the General AI category candidates.
For the OBC AI category candidates, the last round closing rank was 695. For the SC AI and ST AI category candidates, the last round closing ranks were 4912 and 10281. For the PWD AI and EWS AI category candidates, the cutoff was 92797 and 805. Thus, for other categories other than General also, admission at 3
New answer posted
5 months agoContributor-Level 10
The compound microscope comprises two convex lenses - the eyepiece (lower power) and the objective (high power, short focal length). The objective forms a magnified, inverted, and real image of a small object placed just beyond its focal point. Magnifying power is M = (L/f? ) * (D/f? ), where f? is the objective's focal length, L is the tube length, and f? is the eyepiece's focal length. This image acts as the object for the eyepiece.
New answer posted
5 months agoContributor-Level 10
The formula says that for a thin lens, the focal length (f) to its refractive index (? ) and radii of curvature (R? , R? ). Let a thin lens with surfaces of radii R? (first surface) and R? (second surface). We can use the refraction formula to calculate the image formation by the first surface. Following is the formula -? /v -? /u = (? -? )/R. Then we can combine both refractions and assume a lens in air (? = 1).
New answer posted
5 months agoContributor-Level 10
For mirrors and lenses, the Cartesian sign convention is used. For lenses: For convex lenses, the focal length is positive and for concave lenses, it is negative. Distances to the right of the optical center are positive.
For mirrors: For concave mirrors, the focal length is positive and for convex, it is negative. The distances to the right of the optical center are positive. The sign convention allows for consistent calculations for formulas like mirror and lens formulas, and for ray diagrams.
New answer posted
5 months agoContributor-Level 10
Diffraction leads to the formation of patterns of varying intensity. When around obstacles, waves bend and spread through the narrow opening, it is called diffraction. The interference results in a new wave pattern and involves the superposition of two or more coherent waves. Both these phenomena produce patterns of light and dark regions; the interference results from the combination of multiple waves and the diffraction arises from a single wave interacting with an aperture or obstacle. When the size of the aperture or obstacle is comparable to the wavelength of the wave, diffraction patterns are typically observed.
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