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For a given system find out $T_{1}'$ and $T_{2}'$ (forces exerted by the pulley on the support) respectively.

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alok kumar singh

Contributor-Level 10

From F.B. Ds of

$9 k g \to 90 - T_{1} = 9 a \dots . (1)$

$6 k g \to T_{1} - T_{2} = 6 a \dots . . (2)$

$5 k g \to T_{2} - 50 = 5 a \dots . . (3)$

$(1) + (2) + (3)$

$40 = 20 a ? a = 2 m / s^{2}$

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2 weeks ago

In a rocket, fuel burns at the rate of 1 $k g / s .$ This fuel is ejected from the rocket with a velocity of 60 $k m / s$ . This exerts a force on the rocket equal to

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Rate of burning of fuel $(\frac{d m}{d t}) = 1 k g / s$ and velocity of ejected fuel

$(v) = 60 k m / s$

$= 60 * 1 0^{3} m / s .$

Forcev = Rate of change of momentum

$= \frac{d p}{d t} = \frac{d (m ν)}{d t} = v \frac{d m}{d t} = (60 * 1 0^{3}) * 1$

$= 60000$ N.

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A 10 N force is applied on a body produce in it an acceleration of 1 m/s². The mass of the body is

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Contributor-Level 9

Force $(F) = 10 N$ and acceleration

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2 weeks ago

Two blocks of masses 6 kg and 4 kg are connected by a rope of mass 2 kg are resting on a frictionless floor as shown in the following figure. If a constant force of 60 N is applied to 6 kg block, then the tension in the rope at points A,B and C are, respectively, given by

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2 weeks ago

The surface are frictionless, the ratio of T l and $T_{2}$ $_{}$ is

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2 weeks ago

An insect of mass m = 2g is inside a vertical drum of radius 1m that is rotating with an angular velocity of 10 rad/s. If the insect does not fall off then the minimum coefficient of friction is

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Contributor-Level 10

$f ? m g$

$? ? m r ?^{2} ? m g$

$? ? = \frac{g}{r ?^{2}} = \frac{10}{1 * 100} = 0.1$

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2 weeks ago

The ratio of tensions $T_{A} : T_{B}$ in two strings $A$ and $B$ supporting a log of mass $M$ as shown in figure is

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alok kumar singh

Contributor-Level 10

Balancing torque about COM

$T_{A} (\frac{l}{2}) = T_{B} (\frac{l}{6})$

$? \frac{T_{A}}{T_{B}} = \frac{1}{3}$

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2 weeks ago

In case of horse pulling a cart , the force that causes the horse to move forward is the force that

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As per Newton third law, the horse exerts a force on the ground, the ground will also exert a force on the horse.

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2 weeks ago

Two balls each of mass 1kg moving in opposite directions with speed 15m/s collides and rebounds with the same speed. The magnitude of impulse imparted to each ball due to other is

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Contributor-Level 10

l = m (2v) = 1 * 2 * 15 = 30 kg m s^-¹

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2 weeks ago

For the arrangement shown in figure, the tension in the string to prevent it from sliding down, is (g = 10 m/s²)

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