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2 months ago

Overview Class 11th

In two different experiments, an object of mass 5kg moving with a speed of 25 ms^-¹ hits two different walls and comes to rest within (i) 3 second, (ii) 5 seconds, respectively.

Choose the correct option out of the following:

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New question posted

2 months ago

Overview Class 11th

In two different experiments, an object of mass 5kg moving with a speed of 25 ms^-¹ hits two different walls and comes to rest within (i) 3 second, (ii) 5 seconds, respectively.

Choose the correct option out of the following:

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New answer posted

2 months ago

Overview Class 11th

Four forces are acting at a point P in equilibrium as shown in figure. The ratio of force F₁ to F₂ is 1: x where x = _________.

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Vishal Baghel

Contributor-Level 10

$F_{2} = 1 c o s 45 ° + 2 c o s 45 ° = 3 c o s 45 ° = \frac{3}{\sqrt[]{2}} N$

$\begin{array}{l} F_{1} + 1 c o s 45 ° = 2 s i n 45 ° \\ \frac{F_{1}}{F_{2}} = 1 : 3 \end{array}$

x = 3

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2 months ago

Overview Class 11th

A car is moving with speed of 150 km/h and after applying the break it will move 27m before it stops. If the same car is moving with a speed of one third the reported speed then it will stop after travelling _________m distance.

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Vishal Baghel

Contributor-Level 10

Stopping distance = $\frac{v^{2}}{2 a} = d$ $\frac{^{}}{}$

If speed is made $\frac{1}{3} r d$ $\frac{}{}$

$d^{1} = \frac{d}{9}, d^{1} = \frac{27}{9} = 3 m$

Braking acceleration Remains same.

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2 months ago

Overview Class 11th

A uniform chain of 6m length is placed on a table such that a part of its length is hanging over the edge of the table. The system is at rest. The co-efficient of static friction between the chain and the surface of the table is 0.5, the maximum length of the chain hanging from the table is………….m.

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Payal Gupta

Contributor-Level 10

F.B.D. of hanging length

F.B.D. of chain lying on the table

f = T = $μ N$

$\Rightarrow λ x g = μ λ (L - x) g$

$x = 0.5 (6 - x)$

$\Rightarrow x = 3 - 0.5 x$

$1.5 x = 3$

x = 2m

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2 months ago

Overview Class 11th

A stone of mass m, tied to a string is being whirled in a vertical circle with a uniform speed. The tension in the string is

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Payal Gupta

Contributor-Level 10

Is minimum at the highest position of the circular path.

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2 months ago

Overview Class 11th

A block of mass 40kg slides over a surface, when a mass of 4kg is suspended through an inextensible massless string passing over frictionless pulley as shown below.

The coefficient of kinetic friction between the surface and block is 0.02. The acceleration of block is. (given g = 10 ms^-².)

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Payal Gupta

Contributor-Level 10

According to Newton's laws of motion, we can write

4a = 4g – T . (1), and

40a = T - fk = T $μ$ (40g) ……………… (2)

Adding equations (1) and (2), we can write

44a = 40 – 0.02 * (400) = 32

$\Rightarrow a = \frac{32}{44} = \frac{8}{11} m / s^{2}$

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