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New answer posted
4 months agoContributor-Level 9
For ball (a): I? = Δp? = 2mu
For ball (b): I? = Δp? = 2mu cos 45°
I? /I? = 2mu / (2mu cos 45°) = √2
New answer posted
4 months agoContributor-Level 10
Mass m will acquire velocity 2u. Total momentum of system will be conserved but total kinetic energy is not conserved during collision.
New answer posted
4 months agoContributor-Level 10
Given Acceleration of m2 is 2m/s2
(upward)
N = 20a T – m2g = m2a
T – 20g = 20a
T = 200 + 20 * 2
T = 240 N
T = m1 a1
240 = 10a1
a1 = 24 m/s2
F – T – N = Ma2
F – 240 = 100 * 26 + 20 * 26
F = 3360 N
New answer posted
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