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New answer posted

2 days ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

T1 = m (g  + a)

T2 = m (g - a)

 

New answer posted

a week ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

v 1 = 2 g 1 0

v 2 = 2 g 5

l = Δ p

l = 0 . 1 { 2 g 1 0 + 2 g 5 }

= 0 . 1 { 1 0 2 + 1 0 }

= ( 2 + 1 ) N s

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Apparent weight = mg ma

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

As per Newton third law, the horse exerts a force on the ground, the ground will also exert a force on the horse.

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

I = m (2v) = 1 * 2 * 15 = 30 kg m s–1

New answer posted

a week ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Balancing torque about COM

T A l 2 = T B l 6

? T A T B = 1 3

New answer posted

2 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

From equation of uniformly accelerated motion

v = u + a t

7.5 = 15 + 5 a

a = - 1.5 m / s 2

n o w F = m a

F ? = 120 * 1.5

= 180 N

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