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New answer posted

a month ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

For the combined system of mass M and m, the acceleration under an applied force F is:
a = F / (M + m)

The static friction force (f_s) on the top block (m) provides its acceleration:
f_s = MA = m * [F / (M + m)] = mF / (M + m)

For the top block not to slip, the required static friction must be less than or equal to the maximum possible static friction (μmg):
f_s ≤ μmg
mF / (M + m) ≤ μmg
F ≤ μ (M + m)g

Using the values implied in the solution:
F ≤ 21 N

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

N = mg - F_L

f_s = mv²/R ≤ μsN = μs (mg - F_L)

F_L = m (v²/μsR - g)

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Mg + MkV² = MA = -mv (dV/dx)
Vdv = (−) (g + kV²)dx
∫? (Vdv)/ (g + kv²) = ∫? - dx
[ln (g + kV²)/2k]? = -x
ln (g/ (g + ku²) = −2kx
x = (1/2k)ln (1 + ku²/g)

New answer posted

a month ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

mdv? /dt = kv? (1) and mdv? /dt = kv?
(2)/ (1) ⇒ dv? /dv? = v? /v?
v? dv? = v? dv?
v? ² = v? ² + C
v? ² – v? ² = C = Constant
Now, v? * a? = (v? î + v? ) * (k/m) (v? î + v? )
= (k/m) [v? ²k? – v? ²k? ] = (k/m) (v? ² – v? ²)k? = Constant.

New answer posted

a month ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Upward journey

0 - v 0 2 = - 2 g 2 + m g 3 2 s

S = v 0 2 g ( 1 + μ 3 )

Downward journey

v 0 2 4 - 0 = 2 g 2 - 4 g 3 2 v 0 2 g ( 1 + μ 3 )

1 4 = 1 - 3 μ 1 + 3 μ

5 3 = 2 2 3 μ μ = 3 5 = 1732 5

μ = 0.346

I = 346.00

New answer posted

a month ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

V 2 = U 2 + 2 g S V 2 = 0 + 2 g ( h - y ) V 2 = 2 g h - 2 g y V = 2 g h - 2 g y

New question posted

a month ago

0 Follower 3 Views

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

σ4πr² + σ4πR² = Q ⇒ σ = Q/ (4π (R²+r²)
V_c = kq? /r + kq? /R = k (σ4πr²)/r + k (σ4πR²)/R = kσ4π (r+R)
= K (Q/ (R²+r²) (R+r)

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