Physics Current Electricity

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a month ago

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R
Raj Pandey

Contributor-Level 9

J = σ E E ρ = E l R A = 10 * 10 * π 10 * 10 - 4

10 5 A / m 2

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

P = V 2 R P 1 R

P 1 P 2 = R 2 R 1 = 200 100 = 2 1

= 2 : 1

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a month ago

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A
alok kumar singh

Contributor-Level 10

Magnetic energy stored in an inductor = 1 2 L I 2

= 1 2 * 4 * 10 - 6 * ( 2 ) 2 = 8 μ J

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A
alok kumar singh

Contributor-Level 10

? s B ? d A ? = 0 (No monopole exist)

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R
Raj Pandey

Contributor-Level 9

For conductors α α  is (+ve)

For semiconductors α  is (-ve)

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A
alok kumar singh

Contributor-Level 10

R = 22 * 10 3 ± 5 % First band  Red

2nd band =  Red

3rd band =Orange (Multiplier)

4th band = Gold (Tolerance)

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V
Vishal Baghel

Contributor-Level 10

R_eq = (R? )/ (R? +R? ) ⇒ p (l)/ (2A) = [ (p? l/A) (p? l/A)] / [ (p? l/A) + (p? l/A)]

⇒ ρ/2 = (p? )/ (p? +p? ) ⇒ ρ = (2p? p? )/ (p? +p? ) = (2 * 6 * 3)/9 = 4 Ωcm

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a month ago

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V
Vishal Baghel

Contributor-Level 10

12/x = 6/ (72-x) ⇒ x = 144 - 2x ⇒ x = 144/3 = 48cm

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a month ago

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R
Raj Pandey

Contributor-Level 9

R_eq = 10 + (50 * 20) / (50 + 20) = 170/7 Ω
⇒ I = 170 / (170/7) = 7A
⇒ x = 10 * 7 = 70V ⇒ Voltage across 10Ω resistor

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Conduction current density, J? = E/ρ = (V/d) / ρ = (V? sin (2πft) / (pd)
Displacement current density, J? = ε (dE/dt) = (ε/d) (dV/dt) = (2πfε/d) * V? cos (2πft)
The ratio of their magnitudes is:
J? / J? = tan (2πft) / (2πfε? ρ) = tan (2π * 900) / (2π * 9 * 10? * 80ε? * 0.25) = 10?

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