Physics Current Electricity

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4 months ago

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R
Raj Pandey

Contributor-Level 9

R = 22 * 10 3 ± 5 %

First band = = Red

2nd band = Red

3rd band = Orange (Multiplier)

4th band  Gold (Tolerance)

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4 months ago

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V
Vikash Kumar Vishwakarma

Contributor-Level 8

If you want the Current Electricity Class 12 important questions, then check the Class 12 Physics previous year question paper pdf. Also, focusing on the Class 12 Physics past 5 years of exam questions to identify the current electricity class 12 important questions. Well, we have framed all the important questions in the NCERT Physics Class 12 Current Electricity solution pdf, which you can easily download through this article.

New answer posted

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

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A
alok kumar singh

Contributor-Level 10

E 1 E 2 = ? l 1 ? l 2

1.5 2.5 = 36 l 2 l 2 = 36 * 5 3 = 60 c m

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R
Raj Pandey

Contributor-Level 9

At the highest point only horizontal component of velocity remains u x = u c o s ? θ

 

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A
alok kumar singh

Contributor-Level 10

R = R 0 ( 1 + α Δ T )

6.8 = 2 [ 1 + α * ( 80 - 0 ) ] α = 3.4 - 1 80 = 0.03 = 3 * 10 - 2 ? C - 1

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A
alok kumar singh

Contributor-Level 10

B ? P = B ? upper wire   + B ? semi-circle   ? + B ? lower-wire  

B P = - μ 0 i 4 π R + μ 0 i 4 R - μ 0 i 4 π R = μ 0 i 4 R 1 - 2 π  pointing away from the page

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R
Raj Pandey

Contributor-Level 9

J = σ E E ρ = E l R A = 10 * 10 * π 10 * 10 - 4

10 5 A / m 2

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R
Raj Pandey

Contributor-Level 9

P = V 2 R P 1 R

P 1 P 2 = R 2 R 1 = 200 100 = 2 1

= 2 : 1

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A
alok kumar singh

Contributor-Level 10

Magnetic energy stored in an inductor = 1 2 L I 2

= 1 2 * 4 * 10 - 6 * ( 2 ) 2 = 8 μ J

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