Physics Current Electricity

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New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Parallel of  10 k Ω and 400 Ω = 384.61 Ω

V 400 Ω = 384.61 384.61 + 800 * 6 = 1.95 V

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

q V = 1 2 m v 2

v = 2 q V m v q m

v H v H e = 1 1 * 4 1 = 2 1

New question posted

a month ago

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New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

In steady state, capacitor branch is open.
V_AB = 2Ω (1A) + 2Ω (3A) = 8V.

 

New answer posted

a month ago

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alok kumar singh

Contributor-Level 10

V_PQ * (49/100). 1.02 = V_PQ * 0.49. V_PQ ≈ 2.08V.
Potential gradient = 2.08V/100cm = 0.0208 V/cm.

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