Physics Current Electricity

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New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

R? = (ρ? L)/a² R? = (ρ? L)/ (3a²)
Both are in parallel . R? = (R? )/ (R? +R? ) = (ρ? ρ? L)/ (a² (3ρ? +ρ? )

New answer posted

4 weeks ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Potential difference across 2k Ω  is 5V, thus current through it,

i = 5 2 * 1 0 3 = 2 5 * 1 0 4 A .           

New answer posted

4 weeks ago

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R
Raj Pandey

Contributor-Level 9

R e q = 2 . 5 Ω

l = v R e q = 5 2 . 5 = 2 A

New answer posted

4 weeks ago

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R
Raj Pandey

Contributor-Level 9

H = I 2 R t = 2 2 * R * 1 5

3 0 0 = 6 0 R

R = 5 Ω

Now for 3A, time = 10 sec

H ' = l 2 R t = 3 2 * 5 * 1 0 = 4 5 0 J

New answer posted

4 weeks ago

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A
alok kumar singh

Contributor-Level 10

d q d t = t = 2 0 t + 8 t 2

0 q d q = 0 1 5 ( 2 0 t + 8 t 2 ) d t

q = 2 0 * 1 5 2 2 + 8 . 1 5 3 3 = 1 1 2 5 0 C  

New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

i = 6 4 2 + 8 = 0 . 2 A

V x + 4 + 0 . 2 * 8 = V Y

V Y V X = 5 . 6 V

 

New answer posted

4 weeks ago

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R
Raj Pandey

Contributor-Level 9

In galvanometer

( l l g ) S = l g G

I g l = S S + G

1 3 = S S + G S + G = 3 S G = 2 S

New answer posted

4 weeks ago

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V
Vishal Baghel

Contributor-Level 10

Gold band is equal to 5% tolerance

New answer posted

4 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

IgRc = (I - Ig) (S? + S? + S? )
1mA * 10 = 9mA (S? + S? + S? )

New answer posted

4 weeks ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

i series   = E R series  

i series   = E 10 R

i parallel   = E R Parallel  

= E R / 10

i parallel   = n * i series  

10 E R = n E 10 R

n = 100

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