Physics Laws of Motion

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a month ago

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A
alok kumar singh

Contributor-Level 10

for smooth surface

a = g s i n 3 0 ° = g 2

S 1 = u t + 1 2 a t 2         

S 1 = 1 2 g 2 t 2 = g 4 t 2 . . . . . . . ( i )               

for rough Surface

S = 1 2 g 2 ( 1 μ 3 ) α 2 t 2 . . . . . . . . ( i i )               

By (i) and (ii)

μ = 1 3 ( α 2 1 α 2 ) x = 3            

 

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

x = | P + Q | = P 2 + Q 2          

=> y = | P Q | = P 2 + Q 2

| x + y | = x 2 + y 2 + 2 x y

3 ( P 2 + Q 2 ) = ( P 2 + Q 2 ) 2 + ( P 2 + Q 2 ) 2 + 2 ( P 2 + Q 2 ) c o s θ 1

θ 1 = 6 0 °

=>Using same formula : θ2 = 90°

 

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Suppose acceleration of wedge is a and acceleration of block w. r.t. wedge is a1 then N cos60° = Ma = 16 a -> N = 32 a

For block w.r.t. wedge

N + 8a sin 30° = 8g cos 30°

N = 8g cos 30° - 8a sin 30°

->32a = 8g cos 30° - 8a sin 30°

->a = 3 9 g  

Now for 8 kg,

8 g s i n 3 0 ° + 8 a c o s 3 0 ° = m a 1  

a 1 = g * 1 2 + 3 9 g * 3 2  


= 2 3 g  

 

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

For equilibrium net force acting on the system should be zero.

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

M V 0 = M V 1 + m V 2 . . . . ( i )

M V 1 = m V 2  . (ii)
M V 0 2 = M V 1 2 + m V 2 2 . (iii)
M V 0 2 = M V 1 2 + m ( M V 1 m ) 2 [ u s i n g e q n ( i i ) ]
( 1 + M m ) = 4
( M m ) m a x = 3

 

New answer posted

2 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

θ = 6 0 ° 2 = 3 0 °

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

For 8 kg block,

8g – 2T = 8a       . (i)

For 2kg block,

T – 2g = 2 * 2a   . (ii)

Solving equations (i) and (ii),

a = g 4 = 2 . 5 m / s 2              

t = 2 s a = 2 * 0 . 2 2 . 5 = 0 . 4 s              

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

F x = [ 1 0 * 3 2 + 2 0 * 1 2 + 2 0 2 1 5 2 1 5 3 2 ] = 9 . 2 5 i ^

F y = [ 1 5 * 1 2 + 2 0 * 3 2 + 1 0 * 1 2 1 5 2 2 0 2 ] = 5 j ^

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

F. B. D of Beaker

By NLM2    

f = m a = m ω 2 R m ω 2 R μ N R μ g / ω 2

New answer posted

2 months ago

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S
Syed Aquib Ur Rahman

Contributor-Level 10

Newton's First Law is important because it explains the basic concept of a body in motion. The first law implies that an object does not change the state of uniform motion or its state of rest unless a force acts on them. It helps us understand why seat belts, brakes, and handrails are needed. It tells us that a body resists changes already in motion due to inertia, which could lead to accidents without support.

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