Physics NCERT Exemplar Solutions Class 12th Chapter Twelve

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2 months ago

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P
Payal Gupta

Contributor-Level 10

U=ncvT

=2*32*R*300=7479J      

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Payal Gupta

Contributor-Level 10

In case of adiabatic process

Workdone, W=ηR (T2T1)1Y

As, ΔQ=ΔU+W

for adiabatic process :- ΔQ=0

ΔU=W

So, when work is done by the gas, temperature decreases and when work is done on the gas, temperature rises.

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Payal Gupta

Contributor-Level 10

w = P Δ v = n R Δ T = 4 0 0 J  - (1)

Q = n C P Δ T = n R y y 1 Δ T                

Q = 1 4 4 * 4 0 0                

Q = 1400 J

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Payal Gupta

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E 2 > E 1

For statement 1

              hf = E1  - E2

Since, E2 > E1

So, it should be

hf = E2 – E1

Therefore statement 1 is wrong

For statement 2

For the jumping of electron from higher energy orbit

(E2) to lower energy orbit (E1)

hf = E2 – E1

  f = E 2 E 1 h              

Statement (2) is correct

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alok kumar singh

Contributor-Level 10

Sol. eVs=hv-?

 At Vs=0hv=? ? =6.62*10-341014 [5.5]? =6.62*10-341014 [5.5]eV1.6*10-19

=2.27

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Payal Gupta

Contributor-Level 10

At constant Temp

P α 1 v

v2 > v1

⇒ P1 > P2

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Pallavi Pathak

Contributor-Level 10

The NCERT Exemplar given on Shiksha's website provides a variety of numerical, conceptual and application-based questions around energy transitions, atomic models, and spectral series. It is a powerful study material for CBSE Board examination preparation and competitive exams like NEET and JEE.

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Pallavi Pathak

Contributor-Level 10

According to Bohr's postulates, in specific stable orbits, electrons revolve without emitting energy. Energy is only absorbed or emitted when electrons jump between these orbits, preventing them from spiraling into the nucleus.

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Pallavi Pathak

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The concept of quantized energy levels for electrons in atoms is introduced by Bohr's model. Although, Bohr's model could not explain the spectra of multi-electron atoms. It helped lay the foundation for quantum mechanics and successfully explained the spectral lines of hydrogen.

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